Since they are right triangles use Pythagorean Theorem.
a^2 + b^2 = c^2 where c is the hypotenuse.
a. 12^2 + b^2 = 13^2
144 + b^2 = 169
subtract 144 from both sides
b^2 = 25
take the square root of both sides
t = 5 This is also know as a Pythagorean Triple 5-12-13
b. a^2 + 9^2 = 12^2
a^2 + 81 = 144
subtract 81 from both sides
a^2 = 63
take the square root of both sides
a = √63
a = √(9 * 7)
a = 3√7
c. 6^2 + 9^2 = c^2
36 + 81 = c^2
117 = c^2
take the square root of each side
c = √117
c = √(9*13)
x = 3√13
3x-7>2
add 7 to both sides: 3x>9
divide both sides by 3: x>9
A. 2x2 – 4x – 6
Looking at the diagram, there two positive x's to the power of 2, and there are four negative x and six minus signs. Inspecting it and adding all the same terms, you will get the quadratic expression 2x^2 - 4x - 6.
Answer:
(u+2)-8
Step-by-step explanation:
sum is addition, less than is subtraction
