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Rudik [331]
2 years ago
10

7(x-2)=28 Can somebody help me and show the steps?

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
6 0
Since the 7 is in front of the parentheses you must multiply it by everything inside the parentheses. 7 times X is 7X and 7 times -2 is -14. Then you need to make the X be by itself on one side, to do that you have to add 14 to -14 to make it disappear, and also add 14 to the other side, to 28. Then you divide both sides by 7 to make X be by itself.

7(x-2)=28
7X-14=28
7x=42
X=6

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WILL GIVE BRAINLIEST The solution to 15x = 30 is x =___. (Only input the number.)
dedylja [7]

Answer:

x=2

Step-by-step explanation:

If 15x=30 and 15*2=30 then x=2

Hope this helped.

A brainliest is always appreciated.

8 0
2 years ago
Read 2 more answers
Thanks for the help
Brrunno [24]
The answer is B.

In the question it says "the intercept of 6" which means the equation has to have +6 in the answer, and there is only one answer choice containing that.
4 0
3 years ago
Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
Problem 1
Salsk061 [2.6K]

Answer:

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3 0
3 years ago
8x2 - 6x + 3 – 2x – 10x?
Marina CMI [18]

Answer:

8x^{2} + 3 + -6x

Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8x^{2} + 3 + (6x - 2x - 10x)

=> 8x^{2} + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

4 0
3 years ago
Read 2 more answers
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