7(x-2)=28 Can somebody help me and show the steps?
1 answer:
Since the 7 is in front of the parentheses you must multiply it by everything inside the parentheses. 7 times X is 7X and 7 times -2 is -14. Then you need to make the X be by itself on one side, to do that you have to add 14 to -14 to make it disappear, and also add 14 to the other side, to 28. Then you divide both sides by 7 to make X be by itself.
7(x-2)=28
7X-14=28
7x=42
X=6
7(x-2)=28
7X-14=28
7x=42
X=6
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Answer:
Equation:
The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.
Step-by-step explanation:
We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).
The center of this circle is the midpoint of (-3, 4) and (5, -2).
We use the midpoint formula:
Plug in the points to get:
We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:
The equation of the circle is given by:
Where (h,k)=(-1,1) and r=√37 is the radius
We plug in the values to get:
We expand to get:
We want to find at least four points on this circle.
We can choose any point for x and solve for y or vice-versa
When y=0,
The point (5,0) and (-7,0) lies on the circle.
When x=0
The point (0,-5) and (0,7) lie on this circle.