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3 years ago

This distance time graph represents a journey made by Jo

Mathematics

1 answer:

worty [1.4K]3 years ago

5 0

Answer:

a) Jo started <em>coming back</em> to the original starting point.

b) Average Speed of Jo for 30 minutes was <em>11.11 m/s</em>.

Step-by-step explanation:

From the given graph, we can see that

1. From time 0 to 10 minutes, the distance is increasing i.e. Jo is moving away from the starting point.

2. From time 10 to 20 minutes, the distance is decreasing i.e. Jo has started moving back to the starting point where Jo was at time 0 minutes.

3. From 20 minutes to 30 minutes, Jo was at rest.

4. At 30 minutes of time, Jo started moving further at a constant speed (as represented by the straight line).

Part a) When we look at the graph, at time 10 minutes, the line started coming back towards the zero of y axis i.e. distance.

So, Jo started coming back towards his original starting point where Jo was at time 0 minutes.

Time 0 to 10, distance traveled = 1 km

Speed at this time = $\frac{1}{10} km/min = \frac{1000}{10\times 60} m/sec$

Time 10 to 20, distance traveled = 1 km

Speed at this time = $\frac{1}{10} km/min = \frac{1000}{10\times 60} m/sec$

Time 20 to 30, distance traveled = 0 km

Speed from time 0 to 30 minutes:

$Speed = \dfrac{\text{Total Distance Traveled}}{\text{Total Time}}\\\Rightarrow Speed = \dfrac{1+1}{30}\\\Rightarrow Speed = \dfrac{2}{30} km/minute\\\Rightarrow Speed = \dfrac{2000}{30 \times 60} m/sec\\\Rightarrow Speed = 11.11 m/sec$

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Alenkinab [10]

Answer:

$6.79

Step-by-step explanation:

We need to find the cost of a bottle of soap. We divide the cost by the number of bottles

$9.12/6 = $1.52 per bottle

We also need to find the cost for a sponge

$5.00/4 = $1.25 per sponge

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3 years ago

Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1

marta [7]

That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
   A number greater than 10 with a 0 in the units place is a multiple of
   either 5 or 10, so it's not a prime number.

-- 1:
    A number greater than 10 with a 1 in the units place could be
    a prime (11, 31 etc.) but it doesn't have to be (21, 51).

-- 2:
   A number greater than 10 with a 2 in the units place has 2 as a factor
   (it's an even number), so it's not a prime number.

-- 3:
   A number greater than 10 with a 3 in the units place could be
   a prime (13, 23 etc.) but it doesn't have to be (33, 63) .

-- 4:
   A number greater than 10 with a 4 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
   of either 5 or 10, so it's not a prime number.

-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
   A number greater than 10 with a 9 in the units place could be
   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.

It CAN't have a 0, 2, 4, 5, 6, or 8 .

The only choice that includes all of the possibilities is 'A' .

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3 years ago

The time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a

leva [86]

Answer:

Step-by-step explanation:

Given that X the time to complete a standardized exam in the BYU-Idaho Testing Center is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

We have 68 rule as 2/3 of total would lie within 1 std deviation, and 95 rule as nearly 95% lie within 2 std deviations from the mean.

We have std deviation = 10

Hence 2 std deviations from the mean

= Mean ±2 std deviations

= $70$ ±20

= $(50,90)$

Below 50, 0.25 or 2.5% would complete the exam.

3 0

3 years ago

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Nady [450]

Answer:

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Step-by-step explanation:

The width of the rectangle is also the radius of the semicircle. The length of the rectangle is 2 radii, or 14 yd.

The area of the shaded region is the same as the area of the semicircle subtracted from the area of the rectangle.

area of shaded region = area of rectangle - area of semicircle

A = LW - (1/2)(pi)r^2

A = 14 yd * 7 yd - (1/2)(3.14)(7 yd)^2

A = 98 yd^2 - (1.57)(49 yd^2)

A = 98 yd^2 - 76.93 yd^2

A = 21.07 yd^2

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3 years ago

A regular polygon inscribed in a circle can be used to derive the formula for the area of a circle. The polygon area can be expr

Marat540 [252]

Answer:

Option (D)

Step-by-step explanation:

Formula to get the area of a regular polygon in a circle will be,

Area = $n[\frac{1}{2}\times (\text{Base})\times (\text{Height})]$

= $n[\frac{1}{2}\times (\text{s})\times (\text{h})]$

Here 'n' is the number of sides.

If n increases, h approaches r so that 'rh' approaches r².

In other words, if the number of sides of the polygon gets increased, area of the polygon approaches the area of the circle.

Therefore, Option (4) will be the answer.

7 0

4 years ago