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Alex777 [14]
3 years ago
13

A force of 52 N acts upon a 4 kg block sitting on the ground. Calculate the acceleration of the object.

Mathematics
1 answer:
Ahat [919]3 years ago
5 0

Answer:

13m/s

Step-by-step explanation:

F=ma

a=F/m

=52/4

=13m/s

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Jon ran around a track that was 1\8 of a mile long.He ran around the track 24 times.How many miles did Jon run?
balandron [24]

Answer:

3 miles

Step-by-step explanation:

5 0
3 years ago
More help please? ;-;
Vaselesa [24]
Pretty sure it’s 1/2
4 0
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Simplify 3*a*2*b<br> *=multiply
morpeh [17]

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7 0
3 years ago
What is the slope of the line that contains these points? xxx -4−4minus, 4 -3−3minus, 3 -2−2minus, 2 -1−1minus, 1 yyy 222 555 88
Charra [1.4K]

Given:

The table of values is

x        y

-4      2

-3      5

-2       8

-1       11

To find:

The slope of the line that contains these points.

Solution:

From the given table consider any two point.

Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-2=\dfrac{5-2}{-3-(-4)}(x-(-4))

y-2=\dfrac{3}{-3+4}(x+4)

y-2=\dfrac{3}{1}(x+4)

Using distributive property, we get

y-2=3x+12

y=3x+12+2

y=3x+14

Therefore, the required equation of line is y=3x+14.

4 0
3 years ago
How do i solve this?
bixtya [17]

Answer:

5.x^8.y^3

Step-by-step explanation:

15.x^10.y^5.z^2 ÷ 3.x^2.y^2.z^2

= 15/3. x^(10-2). y^(5-2). z^(2-2)

= 5.x^8.y^3.z^0

= 5.x^8.y^3

7 0
3 years ago
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