Given:
The table of values is
x y
-4 2
-3 5
-2 8
-1 11
To find:
The slope of the line that contains these points.
Solution:
From the given table consider any two point.
Let the line passes through the points (-4,2) and (-3,5). So, the equation of the line is




Using distributive property, we get



Therefore, the required equation of line is
.
Answer:
5.x^8.y^3
Step-by-step explanation:
15.x^10.y^5.z^2 ÷ 3.x^2.y^2.z^2
= 15/3. x^(10-2). y^(5-2). z^(2-2)
= 5.x^8.y^3.z^0
= 5.x^8.y^3