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lutik1710 [3]
4 years ago
6

What is 485 times 34

Mathematics
2 answers:
Svet_ta [14]4 years ago
4 0
The answer is sixteen thousand four hundred ninety
Vilka [71]4 years ago
4 0

Answer:

1,419 is your answer

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) Mr. Rivera is making a healthy dessert for his nephew who has diabetes. He wants
Rus_ich [418]

Answer:

see below

Step-by-step explanation:

Apple crisp has

8 servings and contains 80 grams of sugar.

80 grams / 8 servings = 10 grams per serving

Greek frozen yogurt has

12 servings  and contains 60 grams of sugar.

60 grams / 12 serving = 5 grams per serving

He should make Greek frozen yogurt

8 0
4 years ago
Read 2 more answers
Using point-slope form, write an equation of the line that passes through (2,-1) and has a slope of -5
expeople1 [14]
Y – y1 = m(x – x1)

y-(-1)=-5(x-2)

Y+1=-5(x-2)
5 0
3 years ago
Please help me solve the first one and show all work
Leto [7]
Acc. to midpoint theorem,

15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x

WZ= 4x-15
=4*6-15
=24-15=9

3 0
3 years ago
7) Write as a numeral:<br> 40,000 + 7,000 + 600 + 40 + 3
Diano4ka-milaya [45]

Answer:

47,643

Step-by-step explanation:

This question is basically asking you to add up all of these numbers together and present the end result.

1) 40,000 + 7,000 = 47,000

2) 600 + 40 + 3 = 643

3) 47,000 + 643 = 47,643.

5 0
3 years ago
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
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