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kenny6666 [7]
3 years ago
12

Rearrange the equation so x is the independent variable.y +6 = 5(x-4)y =​

Mathematics
2 answers:
Ronch [10]3 years ago
7 0

Answer:

y=5x-26

Step-by-step explanation:

Oksana_A [137]3 years ago
6 0

Answer:

y=5x-26

Step-by-step explanation:

y+6=5(x-4)

-> y+6=5x-20

-> y=5x-20-6

therefore, y=5x-26

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Please help.
denis23 [38]

9514 1404 393

Answer:

  1. Angle 1 = 139°
  2. Angle 2 = 41°
  3. x = 29; exterior angle = 131°

Step-by-step explanation:

These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.

__

1. 53° +86° = ∠1

  139° = ∠1

__

2. ∠2 +92° = 133°

  ∠2 = 133° -92°

  ∠2 = 41°

__

3. (x +9)° +93° = (4x+15)°

  87 = 3x . . . . . . . . . . . . . . . . subtract x+15°

  29 = x . . . . . . . divide by 3

The exterior angle is ...

  (4x +15)° = (4·29 +15)° = 131° . . . exterior angle

3 0
3 years ago
Bus one had half of the grade eight students and 6 grade, seven students, bus two had 15 grade seven students and one-third of g
Rzqust [24]
I'm not sure about that one
7 0
4 years ago
1. Which of the following describes the end behavior of the function ƒ(x) = x^4 + 3x^3 – 2x + 7?
snow_tiger [21]

Hello, when x tends to \infty the term with the highest degree will lead the behaviour.

In other words.

\displaystyle \lim_{x\rightarrow+\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow+\infty} {x^4}\\\\=+\infty\\\\\\\displaystyle \lim_{x\rightarrow-\infty} {x^4+3x^3-2x+7}\\\\=\lim_{x\rightarrow-\infty} {x^4}\\\\=+\infty

So, the answer B is correct.

Thank you.

6 0
3 years ago
A parabola has a vertex at (-2,6) and roots at 7 and m. Find the value of m
Archy [21]

Answer:

So m= - 11

Step-by-step explanation:

* THe vertex is (-2,6), then the equation is y = a(x+2)^2 +6, a is to find out.

* A root is 7 means x=7 and y=0, then :

0 = a(7+2)^2 +6

0=81a+6 or a= -6/81  = -2/27.

* We have the equation: y= -2/27 (x+2)^2 +6=-2/27 [ (x+2)^2-81]

y= -2/27 (x-7)( x+11).

So m= - 11

Hope that you understand.

8 0
4 years ago
What is the perimeter of ΔABC?
Serggg [28]

Answer:

Choice D:  Perimeter = 5 + \sqrt{65} +  \sqrt{34}  units

Step-by-step explanation:

point B(9, 2)  , point C(4, 5),  point A (1,1)

Perimeter = D( A, C)  + D (A, B)  + D (B, C)

where D (A, C) =  distance between A and C

so...

D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5   from a 3-4-5 right triangle.

D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)

D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)

Perimeter = 5 + root(65) + root(34)

Perimeter = 5 + \sqrt{65} +  \sqrt{34}  units

6 0
3 years ago
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