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3 years ago

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Mathematics

1 answer:

Anna35 [415]3 years ago

8 0

Answer:

A = 1.02 P

Step-by-step explanation:

A = P + 0.02P

Formula in Factorized form

(Taking P common)

A = P(1+0.02) [The required factorized from]

Then,

A = 1.02 P

You might be interested in

Factor -1/4 out of -1/2x -5/4y. (i will mark brainlyest)

mash [69]

Answer:

-1/4 (2x - 5y)

Step-by-step explanation:

For us to factor -1/4 out of -1/2x -5/4y

We will have to multiply the values in bracket by the reciprocal of -1/4 i.e -4 as shown

-1/2x - 5/4 y

= -1/4 (-4(-1/2x) - (-4)(-5/4y))

= -1/4 (4/2 x - 20/4 y)

= -1/4 (2x - 5y)

Hence the factored expression is -1/4 (2x - 5y)

5 0

2 years ago

Help plz how many pounds of peanuts will each person get if 3 people share 1/5 pound of peanuts equally

dsp73

Each person will get peanuts
1/3×1/5
=1/15pound

7 0

3 years ago

Lorenzo's bean plant grew 6/10 of an inch everyday. How tall was the plant after 7 days?

4vir4ik [10]

6/10 of an inch= 0.6
7 (times) 0.6 (equals) 4.2

8 0

2 years ago

Read 2 more answers

Futhe Mathematics <img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2

Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

$\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }$

We can write the numerator as ,

$\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }$

Recall the identity ,

$\longrightarrow (a-b)(a+b)=a^2-b^2$

Using this we have ,

$\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}$

Again , as we know that ,

$\longrightarrow sin^2\phi + cos^2\phi = 1$

Therefore we can rewrite it as ,

$\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}$

Again using the first identity mentioned above ,

$\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}$

Or else we can also write it using ,

$\longrightarrow cos2\phi = cos^2\phi - sin^2\phi$

Therefore ,

$\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}$

And we are done !

$\rule{200}{4}$

Additional info :-

Derivation of cos²x - sin²x = cos2x :-

We can rewrite cos 2x as ,

$\longrightarrow cos(x + x )$

As we know that ,

$\longrightarrow cos(y + z )= cosy.cosz - siny.sinz$

So that ,

$\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)$

On simplifying,

$\longrightarrow cos(x+x) = cos^2x - sin^2x$

Hence,

$\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}$

$\rule{200}{4}$

7 0

2 years ago

Meredith and her brother liam are saving to buy a basketball hoop that coats $75. Meredith earns $15 each week for babysitting a

Kay [80]

15x-6+10x-4 = 75

I think this is correct. I had a problem similar to this, and this was the kind of way it was set up

6 0

3 years ago