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3 years ago

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There are 35 boys in the sixth grade. The number of girls in the sixth grade is 42. Lonnie says that means the ratio of the numb

er of boys in the sixth grade is 5:7. Is Lonnie correct?

1 answer:

Keith_Richards [23]3 years ago

7 0

No, Lonnie is not correct because the correct answer is 5/6. If you do 35/42 divide both by 7, it'll be 5/6.

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How many solutions are there to the functions? f(x)=3x+7

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Answer:

A. 0

Step-by-step explanation:

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3 years ago

Steven wants to increase the number of books he reads per year. He currently reads 2 books a year. He wants to triple the number

Sladkaya [172]

Answer:

$B=2\times 3^n$

Step-by-step explanation:

<u>Exponential Growing </u>

Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read

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By the second year, he should read

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By the third year, he should read

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3 years ago

Determine the solution set of (2x - 5)2 = 11.

zhenek [66]

I think what you meant was

(2x - 5)² = 11 -- (1)

Square root both sides of (1), i.e.

√(2x - 5)² = ± √11 -- (2)

From (2), we have

2x - 5 = ± √11 -- (3)

By adding 5 to both sides in (3), we have

2x = 5 ± √11 -- (4)

Divide both sides of (4) by 2, and we obtain

x = (5 ± √11)/2 -- (5)

From (5), the solution set of (1) is

x = (5 + √11)/2, (5 - √11)/2 ...Ans.

8 0

3 years ago

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TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$

Therefore, the values of $b$ are:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

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