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3 years ago

In sale the normal price is reduced by 10% Nathalie bought a pair of shoes in the sale of 54 whats the original price

Mathematics

1 answer:

Sholpan [36]3 years ago

5 0

$59.40 was the original price for the shoes

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What do you multiply to get 8 and add to get 4

nasty-shy [4]

Hi Mitchell

-1*8+12

(-1*8)+12

-8+12=4

I hope that's help :0

3 0

3 years ago

Type the correct answer in the box.

Akimi4 [234]

Answer:

$\huge\boxed{-8+8i}$

Step-by-step explanation:

$2(-36-3i)+(5+2i)(12-2i)\\\\\text{use the distributive property and FOIL}\\\\=(2)(-36)+(2)(-3i)+(5)(12)+(5)(-2i)+(2i)(12)+(2i)(-2i)\\\\=-72-6i+60-10i+24i-4i^2\\\\i=\sqrt{-1}\to i^2=-1\\\\=-72-6i+60-10i+24i-4(-1)=-72-6i+60-10i+24i+4\\\\=(-72+60+4)+(-6-10+24)=-8+8i$

7 0

3 years ago

Please answer this question

ICE Princess25 [194]

Answer:

A: 77

Step-by-step explanation:

360 - 109 - 137 - 37 = 77

3 0

2 years ago

You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave

Rashid [163]

Answer:

List_of_students = {}; //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ; //Variable Stores average score

Below_Average = []; //That is initially filled with zeros

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

Average_score = Average_score + List_of_students(i);

if ( i = 15)

{

Average_score = Average_score / Number_of_students;

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

if ( List_of_students(j) < Average_score)

{

print( "student %name got %score , List_of_students(j), List_of_students(j) )

}

Compare_Score = 0; //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

if ( List_of_students(k) => Compare_Score)

{

Compare_Score = List_of_students(k);

}

Highest_Score = Compare_Score;

Step-by-step explanation:

4 0

3 years ago

Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)

LUCKY_DIMON [66]

To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
$\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )$
$\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}$

Now we can factor both numerator and denominator and simplify:
$\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}$

We can conclude that the difference in simplest form is: $\frac{2}{s-2}$

5 0

3 years ago

Read 2 more answers