$1)\ \ \ sin(- \alpha )=-sin \alpha \\2)\ \ \ cos2 \alpha =1-2sin^2 \alpha \ \ \ \Rightarrow\ \ \ 2sin^2 \alpha =1-cos2 \alpha \\\\ \Rightarrow\ \ \ sin \alpha = \sqrt{\frac{\big{1-cos2 \alpha}}{\big{2}}} \\\\\\sin(-15^0)=-sin15^0=-\sqrt{\frac{\big{1-cos30^0}}{\big{2}}} =-\sqrt{\frac{\big{1- \frac{ \sqrt{3} }{2} }}{\big{2}}} =-\sqrt{\frac{\big{2- \sqrt{3}}}{\big{4}}} =\\\\ =- \frac{1}{2} \sqrt{2- \sqrt{3}}$

7 0

3 years ago

Graded Assignment

san4es73 [151]

Answer:

1.) Amount of potting soil purchased last week.

2) 2p + 4 = 28

3.) 12 lbs

Step-by-step explanation:

1.) The unknown information is what we intend to find out using the information given, which is the amount of potting soil Emmanuel bought last week.

2.)

Let amount of potting soil bought last week = p

Amount bought this week = 2p + 4

Since amount bought this week = 28

Hence, we have ;

28 = 2p + 4

28 - 4 = 2p

24 = 2p

p = 24 / 2

p = 12

8 0

2 years ago