Question

4. A rectangle-shaped picture frame has a length of 4b cm and an area of 12ab² square cm. Find the width.

Answer 1

Answer:

$\boxed{\sf Width \ of \ the \ rectangle = 3ab}$

Given:

Length of the rectangle = 4b cm

Area of the rectangle = 12ab² square cm

To Find:

Width of the rectangle

Step-by-step explanation:

$\sf \implies Area \: of \: the \: rectangle = Length \times Width \\ \\ \sf \implies 12 a{b}^{2} = 4b \times Width \\ \\ \sf \implies Width \times 4b = 12a {b}^{2} \\ \\ \sf Divide \ both \ side \ by \ 4b: \\ \sf \implies Width \times \frac{4b}{4b} = \frac{12a {b}^{2} }{4b} \\ \\ \sf \frac{4b}{4b} = 1: \\ \sf \implies Width = \frac{12 a{b}^{2} }{4b} \\ \\ \sf \implies Width = \frac{3ab \times \cancel{4b}}{ \cancel{4b}} \\ \\ \sf \implies Width = 3ab$