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3 years ago

After traveling steadily at 400 meters above a shipwrecked hull, a submerged vessel starts to descend when its ground distance

Mathematics

2 answers:

Minchanka [31]3 years ago

5 0

Answer:

im trying to find this answer too dont worry :(

Step-by-step explanation:

I dont know

mash [69]3 years ago

3 0

Answer:

Option B, $3.27$

Step-by-step explanation:

Given -

The submerged vessel travel horizontal distance above the shipwrecked hull

$= 400$

$= 0.4$ kilometers

The vertical distance from the the shipwrecked hull to the ground is equal to $7$ kilometers

There forms a right angled triangle with

Base $= 7$ kilometer

Perpendicular $=$ 0.4 kilometer

Tan (angle) $= \frac{Perpendicular}{Base}$

Substituting the given values we get -

Angle of depression

$= tan^{-1}(\frac{0.4}{7})\\= 3.27$

Hence, option B is correct.

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3 years ago

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postnew [5]

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3 years ago

3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3

ozzi

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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VikaD [51]

Answer:

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