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3 years ago

After traveling steadily at 400 meters above a shipwrecked hull, a submerged vessel starts to descend when its ground distance

Mathematics

2 answers:

Minchanka [31]3 years ago

5 0

Answer:

im trying to find this answer too dont worry :(

Step-by-step explanation:

I dont know

mash [69]3 years ago

3 0

Answer:

Option B, $3.27$

Step-by-step explanation:

Given -

The submerged vessel travel horizontal distance above the shipwrecked hull

$= 400$

$= 0.4$ kilometers

The vertical distance from the the shipwrecked hull to the ground is equal to $7$ kilometers

There forms a right angled triangle with

Base $= 7$ kilometer

Perpendicular $=$ 0.4 kilometer

Tan (angle) $= \frac{Perpendicular}{Base}$

Substituting the given values we get -

Angle of depression

$= tan^{-1}(\frac{0.4}{7})\\= 3.27$

Hence, option B is correct.

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Step-by-step explanation:

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3 years ago

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3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

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3 years ago

Solve the inequality.

Dima020 [189]

Answer:

Step-by-step explanation:

x + 8 < - 28

x < - 28 - 8

x < - 36

Option A is the correct answer

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3 years ago