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snow_lady [41]
4 years ago
7

What is the mean of a random variable that is uniformly distributed in [1/2,1] interval?

Mathematics
1 answer:
amm18124 years ago
6 0

Answer:

3/4.

Step-by-step explanation:

The mean is 1/2*(1/2 + 1)

= 1/2 * 3/2

= 3/4.

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A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
3 years ago
Find the shaded area​
ziro4ka [17]

Answer:

24 cm²

Step-by-step explanation:

The area of the shaded region is the area of the outer triangle subtract the area of the rectangle.

Area of triangle = 0.5 × (4 + 4) × (6 + 2) = 0.5 × 8 × 8 = 4 × 8 = 32 cm²

Area of rectangle = 4 × 2 = 8 cm², hence

Shaded area = 32 - 8 = 24 cm²

5 0
3 years ago
HELLO THERE. THIS IS A GEOMETRY QUESTION. ONE REAL ANSWER EQUALS ONE LIKE AND MAYBE BRAINLYIST IF IT ALLOWS ME.
nydimaria [60]

Answer:

104°, 38°, 104°, 38°

Step-by-step explanation:

∠1= ∠3 as opposite angles

and ∠2= ∠4= 38°

∠1= ∠3= 180- 2*38°=104°

4 0
3 years ago
May you please help me it's very confusing for me. ​
pychu [463]

Answer:

First row going down

29=5x-1

x=6

3x+7=28

x=7

58=5x+3

x=11

48=3x+3

x=15

Second row going down

3+4x=23

x=5

9+ x/3 =13

x=12

4x-13=27

x=10

7x+8=15

x=1

Third row going down (starting from top)

2x+1=7

x=3

3x-2=10

x=4

x/2 +5=6

x=2

10=8+x/4

x=8

2x/3=6

x=9

12+x/5=12

x=0

18=3x/4

x=24

4 0
3 years ago
Identify the middle line for the function.
Ierofanga [76]
The solution to the problem is as follows:

<span>'(t) = 0 gives:
 
-24t + 60 = 0
 
t = 2.5
 
For this t, the second derivative s"(t) = -24 is negative.

And so, s(t) is maximum for t = 2.5.
 
Maximum height is:
 
S = -12(2.5)^2 + 60(2.5) +8 = 233ft
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
7 0
3 years ago
Read 2 more answers
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