Pentagon PQRST and its reflection, pentagon P'Q'R'S'T', are shown in the coordinate plane below:

Mathematics

2 answers:

Vlada [557]2 years ago

4 0

To get from pentagon PQRST to P'Q'R'S'T' by a reflection of
A) y = x

Andreas93 [3]2 years ago

3 0

Answer:

Option A y = x

Step-by-step explanation:

In the given figure Pentagon PQRST and its reflection Pentagon P'Q'R'S'T' have been shown.

Pentagon P'Q'R'S'T' have been reflected by a line that passes through origin (0,0) and is perpendicular to the line joining points S(-2,1) and S'(1,-2)

Let the line is y = mx + c

Since line passing through s and s' and slope = $(\frac{y-y'}{x-x'} )$ = $\frac{-2-1}{1+2}=\frac{-3}{3}$ = -1

So line perpendicular to SS' will be

m × (-1) = (-1)

m = 1

The given line will be y = x + c

Since this line passes through (0,0) origin so 'C' will be zero.

Now we can say equation of the line is y = x by which Pentagon PQRST has been reflected.

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