So what we do is area that remains=total area-triangle area that was cut out
we need to find 2 things total area triangle area
total area=rectange=base times height area=(3x+4) times (2x+3) FOIL or distribute 6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height triangle area=1/2 times (2x+2) times (x-2)= (x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so total area=6x^2+17x+12 triangle area=x^2-4
subtract area that remains=total area-triangle area that was cut out area that remains=6x^2+17x+12-(x^2-4)= 6x^2+17x+12-x^2+4= 6x^2-x^2+17x+12+4= 5x^2+17x+16
Ht of ceiling = 10 ft which is two-thirds of living rm ceiling Ht of living rm ceiling = 2/3x = 10 ft 2/3h = 10 ft 2/3h times 3/2 to solve for h = 10 times 3/2 h = 30/2 h = 15 ft
If x is the length of one side of the square, the total width of the cardboard has two squares cut from it. The amount of width remaining is the width of the box. Since the original width of the cardboard is 10, the width of the box is ...
