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Vikki [24]
4 years ago
7

328,000 mm + 137 m = ______________m?

Physics
1 answer:
svp [43]4 years ago
5 0

Answer:

465m.

Explanation:

Convert all units to meters. So,

328 + 137 = 465m.

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Gold's natural state has a definite shape and a definite volume. What is gold's natural state(s)?
zysi [14]

solid

Explanation:

because it has a definite shape and volume

8 0
4 years ago
A solenoid coil 10cm long has 40 turns cm-1. The current rises from zero to its maximum value of 5.0000 A and 0000.01s when the
Crank

Answer:

Explanation:

Energy stored in a solenoid per unit volume = B₀² / (2μ₀)

B₀= μ₀ n I₀

n is no of turns per unit length .

Energy stored in a solenoid per unit volume = ( μ₀ n I₀)² / (2μ₀)

=μ₀n²I₀²/2

n = 40 turns / cm = 40 x 100 turns per meter.

I₀ = 5000A .

Putting the values

Energy stored in a solenoid per unit volume

= 4π x 10⁻⁷ x 40 x 10² x 5000² /2

= 1256 J/ m³

Volume of solenoid = cross sectional area  x length

= 28 x 10⁻⁴ x .10 = 2.8 x 10⁻⁴ m³

Total energy stored = 1256  J / m³ x 2.8 x 10⁻⁴ m³

= .35 J .

3 0
3 years ago
Where is the potential energy of a magnet stored?
Georgia [21]

Answer:

I think it is In the magnetic field

Explanation:

why is because in the electric field is wrong. Please don't use these to cheat these are for you help.

5 0
3 years ago
What is one defining feature of a prokaryotic cell
trapecia [35]
A. nucleus
hope this helps if so please mark me brianliest
5 0
3 years ago
A solid steel cylinder is standing (on one of its ends) vertically on the floor. The length of the cylinder is 3.2 m and its rad
maksim [4K]

To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

\Upsilon = \frac{F/A}{\Delta L/L_0}

Where,

F = Force/Weight

A = Area

\Delta L= Compression

L_0= Original Length

According to the values given we have to

\Upsilon_{steel} = 200*10^9Pa

\Delta L = 5.6*10^{-7}m

L_0 = 3.2m

r= 0.59m \rightarrow A = \pi r^2 = \pi *0.59^2 = 1.0935m^2

Replacing this values at our previous equation we have,

\Upsilon = \frac{F/A}{\Delta L/L_0}

200*10^9 = \frac{F/1.0935}{5.6*10^{-7}/3.2}

F = 38272.5N

Therefore the Weight of the object is 3.82kN

4 0
3 years ago
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