Answer:
A_resulting = 0.2 m
Explanation:
Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.
With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is
A_res = 2A
A_resultant = 2 .01
A_resulting = 0.2 m
Answer:
The property of sugar which makes it different from sand is that sugar can dissolve in water. Explanation: however the power of dissolving of sand is not present. This is due to the presence of interaction between sugar and water.
Explanation:
I hope that was useful
Answer:
The thickness of the oil slick is ![1.95\times10^{-7}\ m](https://tex.z-dn.net/?f=1.95%5Ctimes10%5E%7B-7%7D%5C%20m)
Explanation:
Given that,
Index of refraction = 1.28
Wave length = 500 nm
Order m = 1
We need to calculate the thickness of oil slick
Using formula of thickness
![2nt= m\lambda](https://tex.z-dn.net/?f=2nt%3D%20m%5Clambda)
Where, n = Index of refraction
t = thickness
= wavelength
Put the value into the formula
![2\times1.28 \times t=1\times\times500\times10^{-9}](https://tex.z-dn.net/?f=2%5Ctimes1.28%20%5Ctimes%20t%3D1%5Ctimes%5Ctimes500%5Ctimes10%5E%7B-9%7D)
![t = \dfrac{1\times\times500\times10^{-9}}{2\times1.28 }](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7B1%5Ctimes%5Ctimes500%5Ctimes10%5E%7B-9%7D%7D%7B2%5Ctimes1.28%20%7D)
![t=1.95\times10^{-7}\ m](https://tex.z-dn.net/?f=t%3D1.95%5Ctimes10%5E%7B-7%7D%5C%20m)
Hence, The thickness of the oil slick is ![1.95\times10^{-7}\ m](https://tex.z-dn.net/?f=1.95%5Ctimes10%5E%7B-7%7D%5C%20m)
Since Astronaut and wrench system is isolated in the space and there is no external force on it
So here momentum of the system will remain conserved
so here we can say
![m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}](https://tex.z-dn.net/?f=m_1v_%7B1i%7D%20%2B%20m_2v_%7B2i%7D%20%3D%20m_1v_%7B1f%7D%20%2B%20m_2v_%7B2f%7D)
initially both are at rest
so here plug in all values
![0 = 100 v_{1f} + 2\times 10](https://tex.z-dn.net/?f=0%20%3D%20100%20v_%7B1f%7D%20%2B%202%5Ctimes%2010)
![v_{1f} = -0.20 m/s](https://tex.z-dn.net/?f=v_%7B1f%7D%20%3D%20-0.20%20m%2Fs)
so here the astronaut will move in opposite direction and its speed will be equal to 0.20 m/s
Answer:
(a) v = 3..6 m/s
(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.
Explanation:
from the question we have the following:
mass of the car (Mc) = 24,000 kg
initial velocity of the car (u) = 4 m/s
mass of water (Mw) = 3000 kg
final velocity of the car (v) = ?
(a) we can calculate the final momentum of the car by applying the conservation of momentum where
initial momentum = final momentum
Mc x U = (Mc + Mw) x V
24000 x 4 = (24000 + 3000) x v
96,000 = 27000v
v =3.6 m/s
(b) The rain falling downward has been able to affect the horizontal motion of the car by reducing it's velocity from 4 m/s to 3.6 m/s.