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Natasha2012 [34]
3 years ago
5

11. x2 + 6x - 16 = 0

Mathematics
2 answers:
nataly862011 [7]3 years ago
5 0

Answer:

(x+8)(x-2) roots = -8 and 2

olga55 [171]3 years ago
5 0

Answer:Yes

Step-by-step explanation:

Its right.

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Y= 1x 
i think the y-intercept is 0 but idk
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4 years ago
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Can anyone help me with this question please.
ExtremeBDS [4]

Answer:

see explanation

Step-by-step explanation:

∠ 1 = ∠ 4 ( corresponding angles ), then

∠ 1 = 102°

∠ 2 = ∠ 3 ( corresponding angles ), then

∠ 2 = 78°

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3 years ago
How do you figure out #9 and #10
Ann [662]
#9 the sum of two angles is 90 degrees, creating a right angle.

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4 0
4 years ago
A bag contains white,blue and red balls ratio8:3:2 and there are 10 red balls,if 10 white balls and 10 blue balls are removed fr
dmitriy555 [2]

Answer:

New ratio ( white,blue and red) = 6:1:2

Step-by-step explanation:

Given:

Old ratio ( white,blue and red) = 8:3:2

Number of red balls = 10

Removed balls = 10 white , 10 blue

Find:

New ratio ( white,blue and red)

Computation:

Assume total number of balls = x

So,

Number of total balls = 2x / 13 = 10

Number of total balls = 65

Number of white balls = 40

Number of blue balls = 15

So,

Number of new white balls = 40 - 10 = 30

Number of new blue balls = 15 - 10 = 5

New ratio ( white,blue and red) = 30 : 5 : 10

New ratio ( white,blue and red) = 6:1:2

5 0
3 years ago
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
4 years ago
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