Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
Step-by-step explanation:
Let's call L the length and W the width. The length is 10 feet longer than the width, so:
L = W + 10
The area is the length times width, so:
119 = LW
Substituting:
119 = (W + 10) W
119 = W² + 10W
0 = W² + 10W − 119
0 = (W + 17) (W − 7)
W = -17 or 7
Since W must be positive, W = 7.
L = W + 10
L = 17
The length and width are 17 feet and 7 feet, respectively.
Answer:
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
<h3>given:</h3>
- r=10
<h3>let's solve:</h3>
First you would make the mixed fractions into improper fraction by multiplying the denominator and the whole number, then adding the numerator. Then you would flip the second fraction and multiply.
Ex. 1 1/2 ÷1 1/2
1st. 3/2÷3/2
2nd: 3/2×2/3
3rd 3/2x2/3=1
