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shepuryov [24]
3 years ago
10

14. This week, Anita spent 3 1/2 h practicing the piano. She also spent 6 1/4 h at soccer practice and 4 1/3 h on the telephone.

a) How much time, in total, did Anita spend on the piano and at soccer? b) How much more time did Anita spend at soccer than on the phone?
this is fractions
Mathematics
1 answer:
bixtya [17]3 years ago
4 0
A is 9 3/4 hours. 2/4 equals a half so 1/2 +1/4 equals 3/4
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3 years ago
How many randomly chosen guests should I invite to my party so that the probability of having a guest with the same birthday as
dimulka [17.4K]

Answer:

At least 401 chosen guests

Step-by-step explanation:

Represent those with same birth day with Same

So:

P(Same) > \frac{2}{3}

Represent number of people with n

There are 365 days in a year and 364 days out of these days is not your birthday.

So, there the probability that n people do not share your birthday is (\frac{364}{365})^n

i.e.

P(none) = (\frac{364}{365})^n

Solving further, we have that:

P(same) + P(none) = 1

P(same) + (\frac{364}{365})^n = 1

P(same) = 1 - (\frac{364}{365})^n

We're calculating the probability that P(Same) > \frac{2}{3}.

So, we have:

1 - (\frac{364}{365})^n > \frac{2}{3}

Collect Like Terms

1 - \frac{2}{3}> (\frac{364}{365})^n

\frac{3-2}{3}> (\frac{364}{365})^n

\frac{1}{3}> (\frac{364}{365})^n

3^{-1} > (\frac{364}{365})^n

Take natural logarithm (ln) of both sides

ln(3^{-1}) > ln((\frac{364}{365})^n)

-ln\ 3 > n\ ln\ (\frac{364}{365})

Apply laws of logarithm

-ln\ 3 > n\ (ln(364) - ln(365))

Multiply through by -1

ln\ 3 < n\ (ln(365) - ln(364))

Solve for n

\frac{ln\ 3}{(ln(365) - ln(364))} < n

Reorder

n > \frac{ln\ 3}{(ln(365) - ln(364))}

n > \frac{1.09861228867}{(5.89989735358 - 5.89715386764)}

n> \frac{1.09861228867}{0.00274348594}

n > 400.443928891

n > 400 (approximated)

This implies that n = 401, 402, 403 .....

i.e

n \geq 401

So, at least 401 people has to be invited

5 0
3 years ago
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