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adoni [48]
3 years ago
15

Three electrons are removed from each of 4 atoms. Write an expression to represent the net change on the charge for the group of

atoms.
Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

The charge of each electron is -1, so the charge of three electrons is -3. Removing something is denoted by a negative sign. The expression that represents the removal of three electrons from each of four atoms is (-3)(-4).

Step-by-step explanation:

Enjoy

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Henry has 3 black shirts and 7 blue shirts in his wardrobe. Two shirts are drawn without replacement from the wardrobe. What is
asambeis [7]
Since there are three black shirts and 7 blue shirts, he has a 3/10 chance of picking a black.

6 0
3 years ago
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helpp Jon waits on tables and is paid $5.00 an hour. In a 40-hour period, he earned $210.50 in tips. What were his total earning
Nataly [62]

Add together the income from straight pay and that from tips:

($5/hr)(40 hrs) + $210.50

$200 + $210.50 = $410.50.


Jon's total earnings for the week were $410.50.

7 0
4 years ago
4xy(x cubed +5xy- 7y squared)
VARVARA [1.3K]

Answer:

4x^4y + 20x^2y^2 - 28x^3y

Step-by-step explanation:

4xy(x^3 + 5xy - 7x^2)

= 4xyx^3 + 4xy * 5xy - 4xy * 7x^2

= 4x^2y + 4xy * 5xy - 4xy * 7x^2

= 4x^4y + 20x^2y^2 - 4xy * 7x^2

= 4x^4y + 20x^2y^2 - 28x^3y

4 0
4 years ago
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F(x)=3x2+2x−3 <br><br> g(x)=2x+4
Yakvenalex [24]

Answer:

A: 6

B: 16

C: 2

D: -12

Step-by-step explanation:

They are asking you to multiply the equations:

(3x^2 + 2x - 3)(2x + 4)

Distribute and you should get:

6x^3 + 16x^2 + 2x - 12

The Coefficients A,B,C, and D are 6, 16, 2, and -12.

3 0
3 years ago
A fruit company has 20% returns in periods of normal rainfall and -3% returns in droughts. The probability of normal rainfall is
WARRIOR [948]

Answer:

E(x) = 10.8\% \\\\

The fruit company’s expected returns are 10.8%

Step-by-step explanation:

The expected returns of the fruit company is given by

E(x) =\sum (x \cdot P(x)) \\\\

For the given case,

Returns in normal rainfall = x₁ = 20% = 0.20

Returns in drought = x₂ = -3% = -0.03

Probability of normal rainfall = P(x₁) = 60% = 0.60

Probability of drought = P(x₂) = 40% = 0.40

So, the expected value of returns is

E(x) = x_1 \cdot P(x_1)  + x_2 \cdot P(x_2)  \\\\E(x) = 0.20 \cdot 0.60  - 0.03 \cdot 0.40  \\\\E(x) = 0.12 - 0.012 \\\\E(x) = 0.108 \\\\E(x) = 10.8\% \\\\

Therefore, the fruit company’s expected returns are 10.8%

7 0
3 years ago
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