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____ [38]
3 years ago
8

Let $f(x) = 2x + 7$ and $g(x) = 3x + c$. find $c$ if $(f \circ g)(x) = (g \circ f)(x)$ for all $x$.

Mathematics
1 answer:
boyakko [2]3 years ago
5 0
Let me just rewrite the details in a more understandable manner

f(x) = 2x + 7
g(x) = 3x + c
f( g(x) ) = g( f(x) )

Proceeding to the problem, we have to find the value of c by making use of the relationship written by the third equation. The notation f( g(x) ) means that you have to replace x with g(x). So, you would have incorporate one equation to the other, and vice versa. By equating them, we can determine x. Let us start with f( g(x) ) .

f( g(x) ) = 2(3x + c) + 7
f( g(x) ) = 6x + 2c + 7

Next, we do the similar thing to g( f(x) ).
g( f(x) ) = 3(2x+7) + c
g( f(x) ) = 6x + 21 + c

Then, we equate both simplified equations
6x + 2c + 7 = 6x + 21 + c

Let's simplify further by placing c on one side, and the rest on the other side:
2c - c = 6x - 6x + 21 - 7
c = 14
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

R(1) = 100(\frac{2}{5}.1 )

R(1) = 100(\frac{2}{5} )

R(2) = 100(\frac{2}{5}.2 )

R(2) = 100(\frac{4}{5} )

\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )

\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]

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b. R(0) = 100(\frac{2}{5} .0)

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = 100(\frac{2}{5}.10 )

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

500=100(\frac{2}{5}.t )

\frac{500}{100}=\frac{2}{5}.t

t = \frac{500.5}{100.2}

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0
3 years ago
Help, I need it by 9:00 am
olya-2409 [2.1K]
<h3>Answer:</h3>

Option B. because all rational numbers are integers.

Have a look at the above venn diagram showing the relationship between - Real, irrational, rational, integers, whole and natural numbers.

\longrightarrow{\green{Option \:  B.}}⟶Option  \: B.

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