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2 years ago

3 cm 10 cm 10 cm 3cm

Mathematics

2 answers:

erik [133]2 years ago

8 0

Answer:

what is the question about the given numbers

blondinia [14]2 years ago

6 0

Answer:

your answer is 26cm

Step-by-step explanation:

3cm+10cm+10cm+3cm=26cm. Hope it helps

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Round the number 157 to the nearest tens plce

RUDIKE [14]

The 7 In 157 would round it up to 160. I hope this helps!

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3 years ago

Amy can clean the interior of her car in 3 hours. If Amy and her husband work together,

leva [86]

Answer:

1 hour

Because 3 - 2 = 1.

Therefore, 1 hour only.

5 0

2 years ago

If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?

Lostsunrise [7]

Since $\mathrm M_Y(t)=e^{6(e^t-1}$ , we know that $Y$ follows a Poisson distribution with parameter $\lambda=6$ .

Now assuming $\mu,\sigma$ denote the mean and standard deviation of $Y$ , respectively, then we know right away that $\mu=6$ and $\sigma=\sqrt6$ .

So,

$\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028$

6 0

3 years ago

Translate the following sentence into an equation, then find the number. Five times a number less than 18 is is equal to 13.

Nata [24]

Answer:

The answer would be 5x-18=13

Step-by-step explanation:

When given five times than a number, 5 would be multiplied by (x) since x can be any number. Less than 18 means subtract 18. Is equal to means an eual sign and the equation is equal to 13.

7 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

_______________

$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago

3 cm 10 cm 10 cm 3cm ​

3 cm 10 cm 10 cm 3cm