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shutvik [7]
3 years ago
5

After 3 weeks, a plant is 8 centimeters tall. After 4 weeks, it has grown to 10 centimeters. Of the plant grows following an ari

thmetic sequence, how tall will it be after 25 weeks?
Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

5

Step-by-step explanation:

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Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)
Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }    Simplify inside each bracket

CD = \sqrt{(-16)^{2}+(4)^{2} }    Square the numbers

CD = \sqrt{256+16 }     Add inside the root

CD = \sqrt{272}    Enter into calculator

CD = 16.5  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0
3 years ago
I urgently neeed number 4 plzzzzzzz ASP
pentagon [3]

Answer:  Noah is right. If the mean for the second lake is 60ft and the first lake is 45ft, the second lake has an average depth that is 15 feet deeper.

The standard deviations also indicate that the second lake has some even deeper spots, and even the shallower spots of the second lake are about the same as the shallow spots of the first lake.

Step-by-step explanation:

7 0
3 years ago
If you are going 35 miles per hour, how many miles would you have driven in 3 hours.
Sergeeva-Olga [200]

Answer: you would have driven 105 miles.


Step-by-step explanation: 35x3 = 105


6 0
3 years ago
What is the polynomial 3y2 + (y + 7)2 – 15 after it has been fully simplified and written in standard form?
Greeley [361]

Answer:

4y^2 + 14y + 34

I hope this helps :)

4 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

4 0
3 years ago
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