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e-lub [12.9K]
3 years ago
10

A recipe calls for 3/8 cups of brown sugar for every 2/3 cups of white sugar. How many cups of brown sugar are used per cup of w

hite sugar?
Mathematics
1 answer:
zalisa [80]3 years ago
5 0

Answer:

9/16 Cup of Brown Sugar

Step-by-step explanation:

Convert the 3/8 Cups of Brown Sugar to 6/16 to make division easier.

So for every 2/3 Cup of White Sugar you use 6/16 Cup of Brown Sugar.

So 1/3 a Cup of White Sugar would use 3/16 a Cup of Brown Sugar.

So 3/3 or 1 Cup of White Sugar would use 9/16 a Cup of Brown Sugar

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Δ ABC is isosceles. If m∠A = 100°, m∠B = (12x + 4)°, and m∠C = (14x - 2)°, find x. A) 1 B) 3 C) 5 D) 7
valkas [14]
Since the sum of the angles of a triangle is 180 degrees, we simply have to add all the angles and equate it to 180 to solve for x. So:100 + 12x + 4 + 14x - 2 = 18026x = 78x = 3
So, x is equal to 3.

6 0
3 years ago
How many degrees is StartFraction 15 Over 16 EndFraction pi radians? 84.375° 93.75° 168.75° 337.5°
Leno4ka [110]

Answer:

x = 168.75°

Step-by-step explanation:

<u>Angle Measurement Units</u>

To convert from different units for angle measurements, we have to recall that:

180 degrees = π radians

If we are given the angle in degrees, multiply by π/180 to convert it to radians.

If the angle is given in radians, multiply by 180/π to convert to degrees.

We are given the angle:

\displaystyle x=\frac{15}{16}\pi

Multiplying by 180/π:

\displaystyle x=\frac{15}{16}\pi\cdot \frac{180}{\pi}

Simplifying:

\displaystyle x=\frac{15*180}{16}

x = 168.75°

6 0
3 years ago
Read 2 more answers
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100μ=100 and a standard deviation sigma
Ksivusya [100]

Answer:

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 114, \sigma = 86

Find the probability that a randomly selected adult has an IQ between 86 and 114.

Pvalue of Z when X = 114 subtracted by the pvalue of Z when X = 86. So

X = 114

Z = \frac{X - \mu}{\sigma}

Z = \frac{114 - 100}{20}

Z = 0.7

Z = 0.7 has a pvalue of 0.7580

X = 86

Z = \frac{X - \mu}{\sigma}

Z = \frac{86 - 100}{20}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420

0.7580 - 0.2420 = 0.5160

51.60% probability that a randomly selected adult has an IQ between 86 and 114.

3 0
4 years ago
3m + 5 &gt; 2(m - 7)<br> A m&gt;-12<br> By&gt;12<br> Cm&gt;-19<br> Dm&gt;19
arsen [322]

Answer:

<h2>C. m > -19</h2>

Step-by-step explanation:

3m + 5 > 2(m - 7)

3m + 5 > 2m - 14

3m - 2m > -14 - 5

m > -19

<h2>MARK ME BRAINLIST</h2>
7 0
3 years ago
100,000+4,000+800+5100, comma, 000, plus, 4, comma, 000, plus, 800, plus, 5 in standard form.
8090 [49]

Answer: 109,900,000+4,000+800+5

Step-by-step explanation:

First, let’s add the first four numbers: 100,000 + 4,000 + 800 + 5,100. It equals to 109,900.

Next, after we write 109,900;we write a comma. It’ll look like this: 109,900,

Then, we add 000 after the comma. It is going to be like this: 109,900,000

After that, we add a plus sign: 109,900,000+. We still need to add the 4 and the comma: 109,900,000+4,

Then, we add 000, plus, and 800: 109,900,000+4,000+800. It’ll look like that.

Finally, we need to add the plus and the number 5 to the long equation. It’ll look like this:109,900,000+4,000+800+5.

You’re all done! A little tip is to go in order and not do in whatever order.

Anyways, hope this helped!

8 0
3 years ago
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