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3 years ago

Identify the hypothesis of the statement below.

1 answer:

6 0

Hello Crylicx, <span>If the sum of the measures of two angles is 180° , then the angles are supplementary angles so if you saying if its true or false you answer is correct.</span>

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How do you simplify 8*1/10

Lelechka [254]

Answer:

Improper its 81/10

Step-by-step explanation:

8 1/10~ we should multiply denominator with whole number then add numerator:

10 x 8 = 80+ 1 = 81

In improper its- 81/10

Hope this helps :D

8 0

3 years ago

The area of a right triangle with one leg measuring 5ft and hypotenuse measuring 13ft is

nexus9112 [7]

Calculating the other leg:
other leg^2 = 13^2 - 5^2
other leg^2 = 169 -25
other leg^2 = 144
other leg = 12

Area = .5 * 12 *5
Area = 30 sq feet
answer is A

6 0

3 years ago

Help plz it's solving equations with addition and subtraction but the drawing above is how my teacher wants the answer

saveliy_v [14]

You just finish the equation by adding 19 to 42 which is 61.

5 0

3 years ago

Read 2 more answers

PLEASE HELP WILL MARK BRAINLIEST

exis [7]

Answer:

I can't understand what you wrote but I think it's 594

Step-by-step explanation:

You divide 12 by 2, it is igual to 6.

6 x 33 = 189

189 x 3 = 594

I try to help if it not work :(

3 0

2 years ago

Question 15 (5 points)<br> Find the angle between u = <7, -2> and v= (-1,2>.

Tema [17]

Answer:

Approximately $2.3127$ radians, which is approximately $132.51^{\circ}$ .

Step-by-step explanation:

Dot product between the two vectors:

$\begin{aligned}& u\cdot v \\ =\; & 7 \times (-1) + (-2) \times 2 \\ =\; & (-11) \end{aligned}$ .

Magnitude of the two vectors:

$\begin{aligned} \| u \| &= \sqrt{{7}^{2} + {(-2)}^{2}} \\ &= \sqrt{53} \end{aligned}$ .

$\begin{aligned} \| v \| &= \sqrt{{(-1)}^{2} + {2}^{2}} \\ &= \sqrt{5} \end{aligned}$ .

Let $\theta$ denote the angle between these two vectors. By the property of dot products:

$\begin{aligned} \cos(\theta) &= \frac{u \cdot v}{\|u\| \, \| v \|} \\ &= \frac{(-11)}{(\sqrt{53})\, (\sqrt{5})} \\ &= \frac{(-11)}{\sqrt{265}}\end{aligned}$ .

Apply the inverse cosine function ${\rm arccos}$ to find the value of this angle:

$\begin{aligned} \theta &= \arccos\left(\frac{u \cdot v}{\| u \| \, \| v \|}\right) \\ &= \arccos\left(\frac{(-11)}{\sqrt{265}}\right) \\ & \approx \text{$2.3127$ radians} \\ &= 2.3127 \times \frac{180^{\circ}}{\pi} \\ &\approx 132.51^{\circ}\end{aligned}$ .

8 0

2 years ago