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kykrilka [37]
3 years ago
12

Class A has 25 pupils and class B has 28 pupils. Both classes sit the same maths test. The mean score for class A is 69. The mea

n score for both classes is 41. What is the mean score in the maths test for class B?
Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

13

Step-by-step explanation:

Mean would mean average, which in this case is \frac{x+y}{2}

so your equation would look like \frac{69+x}{2}=41

Next multiply both sides by to clear the fraction 2*(\frac{69+x}{2})

to get 69+x=89

Subtract 69 from both sides 69+x=82\\-69   -69

you get x = 13

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professor190 [17]

Answer:

I'm pretty sure it's 7179.1

Step-by-step explanation:

7179.1

3 0
3 years ago
Need help solving pleaseee!!!
natta225 [31]

Answer:

Step-by-step explanation:

50.

line AB that has the points (2,5) and (9,2) hhas the slope

m= (y2-y1) / (x2-x1)= 5-2 / 2-9 = 3/-7 = -3/7

Parallel line have the same slope so m= -3/7 for the line that has the point (-3,4).

Point-slope equation is y-y1 = m (x-x1), y -4 = -3/4 (x+3) or

you can writte it as y= (-3/4)x - 9/4 +16/4 so y = (-3/4)x + 7/4

51.

line PQ has slope m= -6+1 / 4-6 = -5/-2 = 5/2

Perpendicular lines have their slope negative reciprocal of eachother so the line that goes trough the point (1,3) has the slope m= -2/5

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5 0
3 years ago
A realtor collects the data set given in DS 12.2.4 concerning the sizes of a random selection of newly constructed houses in a c
Yuliya22 [10]

The table is missing in the question. The table is attached below.

Solution :

Let X = appraised value

    Y = area (square feet)

The regression line is given by :

$\hat y = b_0+b_1X$

$b_1=\frac{n\sum XY-\sum X \sum Y}{n \sum X^2-(\sum X)^2}$

   $=\frac{15(5964990)-(2157)(33370)}{15(404799)-(2157)^2}$

  $=12.3267$

$b_0=\frac{\sum Y}{n}-b_1\frac{\sum X}{n}$

   $=\frac{33370}{15}-\left(12.3267 \times \frac{2157}{15}\right)$

  $b_0=452.0841$

The regression line is :

$\hat Y = 452.0841+12.3267 X$

To estimate the error variance, we have:

Error variance, $\sigma =\sqrt{\frac{\sum (Y-\hat Y)^2}n-2{}}$

                           $=\sqrt{\frac{587682.3}{15-2}}$

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8 0
3 years ago
A property sells for $140,000 two years after it was purchased. If the annual appreciation rate is 6%, how much did the original
kykrilka [37]

Answer:

$123,200

Step-by-step explanation:

0.06 x 2 = 0.12

140,000 x 0.12 = 16,800

140,000 - 16,800 = 123,200

3 0
3 years ago
The product of a number and -3, increased by 8, is 20
natita [175]

answer:

-4

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÷-3. = ÷-3

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3 0
3 years ago
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