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viktelen [127]
3 years ago
6

Find a quadratic equation whose roots are the reciprocals of the roots of 3x^2+5x-2=0.

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0
3x^2 + 5x - 2 = 0
3x^2 + 6x - x - 2 = 0
(3x^2 + 6x) + (-x - 2) = 0
3x(x + 2) - 1(x + 2) = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 or x + 2 = 0
3x = 1 or x = -2
x = 1/3 or x = -2

Reciprocals are 3 and -1/2
Equation with roots at 3 and -1/2 is (x - 3)(x + 1/2) = x^2 - 5/2 x - 3/2 = 2x^2 - 5x - 3
Therefore, required equation is y = 2x^2 - 5x - 3
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Step-by-step explanation:

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Let x = the third side

 

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  (Inequality #1)   12 + 4 > x

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  (Inequality#2)    12 + x > 4

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So when we combine these together,  

 

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7 0
2 years ago
PLEASE HELP FAST! THX
mr Goodwill [35]

Answer:

3 ,5 , and 2

Step-by-step explanation:

Hope it helps :)

7 0
3 years ago
I have no idea!!! Help??
Savatey [412]

Answer:

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Step-by-step explanation:

7x -19 < 16

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Open circle at 5  going to the left

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9-9 +3x >12-9

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3 0
3 years ago
Add: (7-5i) (-10+2i)
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Answer:

-10i^(2) + 64i - 70

5 0
3 years ago
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