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ZanzabumX [31]
2 years ago
13

A room measures 15 ft by 20 ft by 10 ft. If a basketball has a diameter of 9.6 inches, approximately how many basketballs will b

e needed to fill the room?
Mathematics
1 answer:
vovangra [49]2 years ago
7 0

Answer:

10344.827586 basketballs

Step-by-step explanation:

A room measures 15 ft by 20 ft by 10 ft. If a basketball has a diameter of 9.6 inches, approximately how many basketballs will be needed to fill the room?

Step 1

We find the volume of the room

The room is rectangular in shape

Volume = Length × Width × Height

= 15ft × 20ft × 10ft

= 3000ft³

Step 2

Basket ball is spherical in shape

Volume of a sphere = 4/3πr³

Diameter = 9.6 inches

Radius = Diameter/2 = 9.6 /2 = 4.8 inches

Convert Radius from inches to ft

= 4.8inches/12

= 0.408333 feet

Volume of a sphere = 4/3 × π × 0.408333³

= 0.29 ft³

Step 3

3000 ÷ 0.29

10344.827586

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<h2>Step-by-step explanation:</h2>

In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether x=10, \ y=-3, \ z=14 is the solution to this system, that is, the ordered triple P(x,y,z) where three planes intersect.

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