find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
Answer:
okay so it would be 2 or 1.5 i dont know if you want it whole number but i will explain
if the number is 5 or more like 5.1 or even 5 you round up
if the number is under 5 like 4,3,2,1 your round down
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
ΔABC is congruent with ΔDEF. That means the corresponding sides are congruent.
Look at the order of the letters. EF are the last two letters of ΔDEF. So this corresponds with the last two letters of ΔABC. Therefore, EF ≅ BC.
EF ≅ BC
x² + 8x = 48
x² + 8x − 48 = 0
(x + 12) (x − 4) = 0
x = -12 or 4
Since x can't be negative, x = 4.
This question is incomplete, the complete question is;
For what value of a is the volume of the tetrahedron formed by the coordinate planes and the plane (x/a) + (y/10) + (z/6) = 1 equal to 10?
Answer: the value of a is 1
Step-by-step explanation:
Given that;
Volume of tetrahedron bounded by plane (x/a) + (y/10) + (z/6) = 1
and coordinate plane is; V = 1/6|abc|
(x/a) + (y/10) + (z/6) = 1
volume = 10
so
10 = 1/6 | a × 10 × 6 |
60 = a × 10 × 6
60 = 60a
a = 60 / 60
a = 1
Therefore the value of a is 1
