Answer:
D variations in individuals are not heritable
Explanation:
Genetic variation in individuals is what drives evolution. In a population of individuals in an environment, with the adequate resources, overpopulation can occur. However, resources are usually a limiting factor for population growth: there is not sufficient food/shelter etc. for everyone to survive.
Some individuals are better suited to success in the environment. This is because of random variation in their DNA that has arisen that give them a selective advantage. This allows them to thrive, take advantage of the limited resources over other members of the population, and be more likely to survive to reproductive age. This is natural selection.
Because this variation is genetic (in the DNA), they can then pass it on to their offspring. Over time, this leads to evolution over time.
Based on the description of events, being that the lizard population appears to increase as soon as the snake population decreases, it appears that the snakes prey on the lizards. This suggests that the snake is a keystone species. A keystone species is one that has a dramatic effect on maintaining the balance of an ecosystem. As soon as the snake population decreases, major changes occur to the ecosystem, such as the lizard population increasing.
Therefore, the answer is D: <span>The snake is a keystone species in the ecosystem.</span>
Answer:
Mass doesn't change no matter where you are or where you go.
Explanation:
Mass is what you or an object consist of. You cant change mass
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
