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Afina-wow [57]
3 years ago
5

What's the answer? Thank you <3

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Remark

You can get it just by looking at the net. It has 6 squares. Each square has a side of 5 cm by 5cm. Find the area of 1 square and multiply by 6.

Step One

Find  the area of one square.

<u>Formula</u>

Area = s^2

<u>Solve</u>

Area for 1 square = s^2 = 5^2 = 25 cm^2

Step Two

Find the area for six squares.

Area of the net = 6*Area of one square = 6 * s^2

6*s^2 = 6 * 25

Area = 150 cm^2


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Fofino [41]
First isolate y by adding x to both sides in y-x=3 and getting y=x+3
Step 1: substitute x+3 for y in 3y=x+6 to get 3(x+3)=x+6
Step 2: distribute 3x+9=x+6
Step 3: subtract like terms 2x=-3
Step 4: divide x=-3/2

substitute -3/2 for x in y=x+3 to get
y=-3/2+3
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answer: y=3/2 x=-3/2
5 0
2 years ago
Please answer this and will marked as brainlist ​
xeze [42]
<h3>Answer: 1</h3>

where x is nonzero

=======================================================

Explanation:

We'll use two rules here

  • (a^b)^c = a^(b*c) ... multiply exponents
  • a^b*a^c = a^(b+c) ... add exponents

------------------------------

The portion [ x^(a-b) ]^(a+b) would turn into x^[ (a-b)(a+b) ] after using the first rule shown above. That turns into x^(a^2 - b^2) after using the difference of squares rule.

Similarly, the second portion turns into x^(b^2-c^2) and the third part becomes x^(c^2-a^2)

-------------------------------

After applying rule 1 to each of the three pieces, we will have 3 bases of x with the exponents of (a^2-b^2),  (b^2-c^2) and (c^2-a^2)

Add up those exponents (using rule 2 above) and we get

(a^2-b^2)+(b^2-c^2)+(c^2-a^2)

a^2-b^2+b^2-c^2+c^2-a^2

(a^2-a^2) + (-b^2+b^2) + (-c^2+c^2)

0a^2 + 0b^2 + 0c^2

0+0+0

0

All three exponents add to 0. As long as x is nonzero, then x^0 = 1

4 0
3 years ago
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5 0
3 years ago
Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.
Rufina [12.5K]

Answer: k = -1 +/- √769

<u>Step-by-step explanation:</u>

48x - ky = 11

<u>-48x        </u>  <u> -48x</u>

         -ky = -48x + 11

         \frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}    

           y =\frac{48x}{k} - \frac{11}{k}

Slope: \frac{48}{k}

*************************************************************************

 (k + 2)x + 16y = -19

<u>- (k + 2)x          </u>   -<u>(k + 2)x </u>

                 16y = -(k + 2)x - 19

                  \frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}

                  y = -\frac{(k + 2)x}{16} - \frac{19}{16}

Slope: -\frac{(k + 2)}{16}

**********************************************************************************

\frac{48}{k} and -\frac{(k + 2)}{16} are perpendicular so they have opposite signs and are reciprocals of each other.  When multiplied by its reciprocal, their product equals -1.

-\frac{(k + 2)}{16} *  \frac{k}{48} = -1

\frac{(k + 2)k}{16(48)} = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769



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3 years ago
The graph shows the distance, y, that a car traveled in x hours:
victus00 [196]

Answer:

Hello, Your answer would be 35 (Fraction 1 over 35)

Hope's this helped.

Step-by-step explanation:

4 0
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