How many area codes (ABC) would be possible if the first 2 digits can be any number 2-9 & last digit can be any number 0-9?

1 answer:

8 0

The answer would be A. 640

Possibilities for the first two are 8 and 8 (2-9 is 8 numbers) and the last is 10 (0-9 is 10 numbers)

So the probability is found by multiplying 8*8*10 which is 640

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