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2 years ago

How many area codes (ABC) would be possible if the first 2 digits can be any number 2-9 & last digit can be any number 0-9?

1 answer:

8 0

The answer would be A. 640

Possibilities for the first two are 8 and 8 (2-9 is 8 numbers) and the last is 10 (0-9 is 10 numbers)

So the probability is found by multiplying 8*8*10 which is 640

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PLS HELP I WILL GIVE BRAINLIEST 1- If you are driving at a constant speed of 55 miles per hour, give an estimate of how many mil

Hatshy [7]

Answer:

1- 72 miles

2-$3

3- 50(0.50 x c)

Step-by-step explanation:

For Number 1 we have to do 55 divided by 60 which is about 0.90 and then we multiply that by 1 hour and 20 minutes which in minutes is 80. 0.90 x 80 = 72 exactly.

For Number 2 we have to divide 36.25 by 11.5 rounded is 36/12 whish is 3.

For number 3 c stands for number of channels

Hope i could help! :DD

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2 years ago

Solve the system graphically: b x−y=0 2x+3y=−5 x= y=

vlabodo [156]

Answer:

(-1,-1)

Step-by-step explanation:

x=y

2x+3x=-5

x=-1

y=-1

6 0

3 years ago

Convert 77 degrees in Fahrenheit to Celsius temperature using the formula . 72°C 61°C 35°C 25°C

faust18 [17]

Answer:

25º celsius

Step-by-step explanation:

The formula for converting fahrenheit to celsius is: Deduct 32, then multiply by 5, then divide by 9

77 - 32 = 45 x 5 = 225/9 = 25º

8 0

2 years ago

Find the linearization of f(x) = x ^ (y / 2) a = 43

Dafna1 [17]

Answer:

DWAFECGSAD

Step-by-step explanation:

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7 0

3 years ago

The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions

Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

$\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}$

The quadratic equation can now be solve using factorization method:

$\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}$

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

$\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\ \\ Width=x=5\text{ }ft \end{gathered}$

7 0

1 year ago