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2 years ago

Can anyone please help!!!!!

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

8 0

Answer:

92.3ft

Step-by-step explanation:

Let the con=rners be A,B,C and d

so AC=105 ft and AB=50ft

using Pythagoras theroem: h^2=b^+p^2

105^2=50^2 + p^2

P^2= 11025-2500

p= √8525

p=92.33

Sedaia [141]2 years ago

3 0

Answer:

your answer is A. 92.4

Step-by-step explanation:

Diagonal Length = v(92.4² + 50²)

V(8537.76 + 2500)

V(1037:76)

Diagonal Length 105

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A number is chosen at random from 1 to 50. Find the probability of selecting numbers greater than 15 and less than 24

Liono4ka [1.6K]

Answer:

4/25

Step-by-step explanation:

4 0

3 years ago

Eduardo has purchased a home with an assessed value of $179,000. The property tax rate in his area is 2.3%. What is his monthly

ad-work [718]

Answer:

C. 343.08

Step-by-step explanation:

Convert the tax rate into a decimal and multiply by the house price:

.023(179,000) = 4,117

Divide by 12 (to get monthly rate):

4,117/12 ≈ 343.08

Option C should be the correct answer.

7 0

3 years ago

The perimeter of a triangle is 17x-5 units. One side is 3.x + 5 units and another is 8x-3 units. How many units long is the thir

Ivahew [28]

Answer:

C = 6x - 7 units

Step-by-step explanation:

Let the three sides of the triangle = A, B, and C respectively.

<u>Given the following data;</u>

Perimeter of triangle, P = 17x-5 units

Side A = 3x+5 units

Side B = 8x-3 units

To find side C?

The perimeter of a triangle is given by the addition of all its three (3) sides.

Mathematically, the perimeter of a triangle is given by the formula;

P = A + B + C

Making "C" the subject of formula, we have;

C = P - A - B

Substituting into the equation, we have

C = 17x - 5 - (3x + 5) - (8x - 3)

C = 17x - 5 - 3x - 5 - 8x + 3

Collecting the like terms, we have;

C = 17x - 3x - 8x - 5 - 5 + 3

C = 6x - 7 units

Therefore, the third side is 6x - 7 units long.

5 0

2 years ago

Plz help this is due today AND NO LINKS OR GROSS PICTURES OR I REPORT

Zina [86]

Answer:

I think its A

Step-by-step explanation:

3 0

2 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago