Answer: 1/4
Explanation:
Firstly, in order for both parents to be type A and have children with type o blood, their blood types must both be Ao. Since o is a recessive blood type, a punnett square shows there is a 25% chance any child of theirs will have type o blood. If neither parent is color blind and they have a son who is, it implies that the mother is a carrier of colorblindness and has the genotype XᴮXᵇ. If you do a punnett square of the not colorblind father (XᴮY) and the mother, it shows that a daughter would have a 0% chance of being colorblind. Therefore colorblindess is irrelevent, since there is no possibility of the daughter not having normal color vision. In conclusion, there's a 25% chance she will have type o blood and not be colorblind, since the other 75% chance would be having type A blood and not being colorblind.
Ten times as much. Did the eagle eat the duck?
I think it's True.. ((:
http://www.chemguide.co.uk/physical/basicrates/catalyst.html
That might help ^
