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Vedmedyk [2.9K]
3 years ago
14

What is the arc measure of AD in degrees?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Angle ABD measures half of arc AD and angle DBC measures half of arc DC. Therefore angle ABC measures half of arc ADC.

We state this as a theorem:

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Can anyone help me with this
marin [14]

Answer:

27

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Of the following equations below, which equation represents a direct variation between x and y?
spin [16.1K]

Answer:

C. y +3 = x +3

Step-by-step explanation:

We need to find in below option x has direct variation with y.

We solve for each;

A. 2y = 3x-7

From above equation we can state that 2 times y is equal to 7 less than 3 times of x.

Hence it doesn't represent direct variation.  

B. y-4 = x+6

Solving above expression we get;

y-4 = x+6\\y = x+6+4\\y=x+10

From above equation we can state that y is equal to 10 more than x.

Hence it doesn't represent direct variation.

C. y+3 = x+3

Solving above expression we get;

y+3 = x+3\\y = x+3-3\\y=x

From above equation we can state that y is equal to x.

Hence it represent direct variation.

D. 4y+1 = 4x-1

Solving above expression we get;

4y+1 = 4x-1\\4y = 4x-1-1\\4y=4x-2

From above equation we can state that 4 times y is equal to 2 less than 4 times of x.

Hence it doesn't represent direct variation.

Hence the Answer which represent direct variation of x and y is,

C. y+3 = x+3

7 0
3 years ago
Is .444 rational or irrational???
Murljashka [212]
Any terminating decimal number is rational.
A rational number is a number that can be written as a fraction of integers.

0.444 = 444/1000 = 222/500 = 111/250

0.444 is the same as 111/250, a fraction of integers, so 0.444 is rational.
6 0
4 years ago
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
3 years ago
How to solve the equations
satela [25.4K]
You would do parentheses first and that answer you will x 7
6 0
3 years ago
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