Answer:
The length on the blueprint for an actual length of 65 feet is 
Step-by-step explanation:
Given:
Scale of the blueprint is 
Length of one side of the house is 65 feet.
Now, as per given data;
1 foot in actual = 
on the blueprint.
Therefore, using unitary method, we can find find the length on the blueprint for an actual length of 65 feet by multiplying 65 and 
. Therefore,
Length on the blueprint for 65 feet is given as:
Therefore, the length on the blueprint for an actual length of 65 feet is
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Y=6x+4
Blanks from left to right:
-14,-2,10,22,6x+4
Let the length of unknown side be x
So, hypotenuse = 2x + 1
By pythagorean theorem ie , a² = b² + c²
(2x + 1)² = x² + 15²
4x² + 1 + 4x = x² + 225
3x² + 4x -224
(3x +28)(x-8)
x = -9.33 , 8
Since, length can't be negative
x = 8
∴Unknown side length = 8 m
Length of hypotenuse = 2 x 8 + 1 = 17 m
Hope it helps now.
