Answer:
(2,0); x = 2; y= 0
Step-by-step explanation:
add the system and u get y = 0. substitute in the first equation and u get x = 2
Prove that DJKL~ DJMN using SAS Similarity Theorem. Plot the points J (1,1), K(2,3), L(4,1) and J (1,1), M(3,5), N(7,1). Draw DJ
dolphi86 [110]
Answer and Step-by-step explanation: The triangles are plotted and shown in the attachment.
SAS Similarity Theorem is by definition: if two sides in one triangle are proportional to two sides of another triangle and the angles formed by those sides in each triangle is congruent, the triangles are similar.
For the triangles on the grid, we know that ΔJKL and ΔJMN have a congruent angle in J as shown in the image. To prove they are similar, we find the slope of sides KL and MN:
<u>Slope of KL</u>:
slope = 
slope = 
slope = -1
<u>Slope of MN</u>:
slope = 
slope = 
slope = -1
Since the slopes of KL and MN are the <u>same</u> and the angle is <u>congruent</u>, we can conclude that ΔJKL~ΔJMN.
Answer:
1. 2(3x−2)(2x−3)
2. 3(3x+1)(2x+5)
3. 2(4x+1)(2x−5)
4. 4(2x+1)(2x+7)
5. 5(3x+1)(2x−5)
6. 3(3x−7)(2x+1)
7. 3(5x+3)(3x−2)
8. 2(7x−2)(2x−5)
9. 2(7x−3)(2x−3)
10. 4(5x−11)(2x+1)
11. 5(x−2)(x+12)
12. (x−1)(x−8)
15. x=1 or x=4
Step-by-step explanation:
1. Factor 12x2−26x+12
12x2−26x+12
=2(3x−2)(2x−3)
2. 3(3x+1)(2x+5)
3. Factor 16x2−36x−10
16x2−36x−10
=2(4x+1)(2x−5)
4. Factor 16x2+64x+28
16x2+64x+28
=4(2x+1)(2x+7)
5. Factor 30x2−65x−25
30x2−65x−25
=5(3x+1)(2x−5)
6. Factor 18x2−33x−21
18x2−33x−21
=3(3x−7)(2x+1)
7. Factor 45x2−3x−18
45x2−3x−18
=3(5x+3)(3x−2)
8. Factor 28x2−78x+20
28x2−78x+20
=2(7x−2)(2x−5)
9. Factor 28x2−54x+18
28x2−54x+18
=2(7x−3)(2x−3)
10. Factor 40x2−68x−44
40x2−68x−44
=4(5x−11)(2x+1)
11. Factor 5x2+50x−120
5x2+50x−120
=5(x−2)(x+12)
12. Let's factor x2−9x+8
x2−9x+8
The middle number is -9 and the last number is 8.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -9
Multiply together to get 8
Can you think of the two numbers?
Try -1 and -8:
-1+-8 = -9
-1*-8 = 8
Fill in the blanks in
(x+_)(x+_)
with -1 and -8 to get...
(x-1)(x-8)
15. Let's solve your equation step-by-step.
(x−2)(x−3)=2
Step 1: Simplify both sides of the equation.
x2−5x+6=2
Step 2: Subtract 2 from both sides.
x2−5x+6−2=2−2
x2−5x+4=0
Step 3: Factor left side of equation.
(x−1)(x−4)=0
Step 4: Set factors equal to 0.
x−1=0 or x−4=0
x=1 or x=4
Sorry I wasn't able to do 13 and 14 but hope this helps! :)