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fenix001 [56]
3 years ago
5

how can we relate the presence if color in an ionic solution as a characteristic lf electron configuration

Chemistry
1 answer:
Debora [2.8K]3 years ago
6 0
Answer:
Colours come from electrons moving between shells. The energy of light matches the energy gaps between electron shells.
Explanation:
Electrons are arranged in energy levels (shells) and there are energy gaps between shells. Electrons must be in one shell and cannot be in between. Electrons can move from one shell to another in the right conditions.
When an atoms absorbs energy from heat or light, the atom starts to move a little faster, in other words, it gets warmer. If the energy absorbed is just right to match the energy gap between shells, electrons can jump from one shell to another.
If an object is red, then the energy between gaps during light absorption is equal to the energy of the complementary light color, green.
If the object emits red light, then the energy between gaps during light emission is equal to the energy of red light.
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The symbol for a radioactive nuclide is 131/56Ba Which statement is correct?A) The atomic number of the radioactive nuclide is 7
stich3 [128]
Hihi!

The correct answer is B. The mass number of this nuclide is 131! It's proton number is 56 and it has 75  neutrons  (131 - 56 = 75 neutrons).

I hope I helped!
-Jailbaitasmr
6 0
3 years ago
Read 2 more answers
Why can't helium bond with hydrogen?
Iteru [2.4K]
Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
8 0
3 years ago
A common car battery consists of six identical cells each of which carries out the reaction: Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 +
docker41 [41]

Answer:

The correct answer is 4.58 grams.

Explanation:

Based on the Faraday's law of electrolysis, at the time of electrolysis, the amount of deposited substance is directly equivalent to the concentration of the flow of charge all through the solution. If current, I, is passed for time, t, seconds and w is the concentration of the substance deposited, then w is directly proportional to I*t or w = zIt (Here z refers to the electrochemical equivalent or the amount deposited when 1 C is passed).  

For the reaction, n * 96500 C = molar mass

1C = molar mass/n*96500 = Equivalent wt / 96500

w = Equivalent wt / 96500 * I * t

In the given reaction,  

Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 + 2H2O, n = 2, the current or I drawn is 350 A, for time, t 12.2 seconds.  

Now putting the values in the equation we get,  

w = 207.19 / 2 * 96500 * 350 * 12.2 ( The molecular weight of Pb is 207.19 and the equivalent weight of Pb is 207.19 / 2)

w = 4.58 gm.  

6 0
4 years ago
11.2 L of gas at a temperature of 25°C are held at a pressure of 1.1 atm. How many moles of gas are contained in the sample?
AysviL [449]
<span>0.5035 so go with .50 moles.
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5 0
3 years ago
Calcule la masa en gramos de cloruro de hidrógeno (HCl) que se forma cuando 5.6 L de hidrógeno molecular, medido a TPE, reaccion
AveGali [126]

Calculate the mass in grams of hydrogen chloride (HCl) that is formed when 5.6 L of molecular hydrogen, measured at TPE, reacts with an excess of gaseous molecular chlorine. MHCl = 36.5 g/mol

H2(g) + Cl2(g) → 2HCl(g)

Answer:

18.25g

Explanation:

The reaction equation is given as;

        H₂   +   Cl₂   →   2HCl

Given parameters:

Volume of hydrogen gas = 5.6L

 The reaction occurs at STP.

Solution:

To solve this problem, let us find the number of moles of the hydrogen as;

          At STP;

    22.4L of a gas has 1 mole;

    5.6L of Hydrogen as will have \frac{5.6}{22.4}   = 0.25mole

From the balanced reaction equation;

        1 mole of H₂  will produce 2 mole of HCl

      0.25 mole of H₂ will produce 2 x 0.25 = 0.5mole of HCl

The mass of HCl';

    Mass of HCl  = number of moles x molar mass

   Mass of HCl  = 0.5 x 36.5  = 18.25g

7 0
3 years ago
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