The amount remaining at the end of 5 half-lives is 7.81×10¹³ g
From the question given above, the following data were obtained:
- Half-life (t½) = 5730 years
- Original amount (N₀) = 2.5×10¹⁵ g
- Number of half-lives (n) = 5
- Amount remaining (N) =?
The amount remaining can be obtained as follow:
N = 1/2ⁿ × N₀
N = 1/2⁵ × 2.5×10¹⁵
N = 1/32 × 2.5×10¹⁵
N = 0.03125 × 2.5×10¹⁵
N = 7.81×10¹³ g
Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g
Learn more about half-life: brainly.com/question/25783920
Answer:
7.41 × 10⁻⁵
Explanation:
Let's consider the basic dissociation reaction of trimethylamine (CH₃)N).
(CH₃)N + H₂O = (CH₃)NH⁺ + OH⁻
According to Brönsted-Lowry, in this reaction (CH₃)N is a base and (CH₃)NH⁺ is its conjugate acid. The pKb for (CH₃)N is 9.87. We can calculate the pKa of (CH₃)NH⁺ using the following expression.
pKa + pKb = 14
pKa = 14 - pKb = 14 - 9.87 = 4.13
Then, we can calculate the acid dissociation constant for (CH₃)NH⁺ using the following expression.
pKa = -log Ka
Ka = antilog - pKa = antilog -4.13 = 7.41 × 10⁻⁵
This is an example of "Skyscrapers".
Explanation:
- Skyscraper is a high rise, tall multi storied building of that consist of about 40 floors inside it that is mainly built for the corporate offices, commercial spaces and residential flats.
- Buildings that are higher than 150m height are known skyscrapers. They have steel or iron framework to its inner side of the building that supports its floor and walls.
- Skyscrapers are made possible by the process of Bessemer process of mass production of steel beam.
From the periodic table:
mass of carbon = 12 grams/mole
mass of hydrogen = 1 gram/mole
mass of oxygen = 16 grams/mole
The given compound C₆H₁₂O₆ has 6 moles of carbon, 12 moles of hydrogen and 6 moles of oxygen.
Therefore, the molar mass of the given compound will be calculated as follows:
molar mass = 6(12) + 12(1) + 6(16) = 180 grams/mole
Salt water is a Homogeneous Mixture......
