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11Alexandr11 [23.1K]
3 years ago
13

Why can a solution be classified as a mixture

Chemistry
2 answers:
Vanyuwa [196]3 years ago
7 0
Because they’re both made up of two substances that are not chemically combined
GalinKa [24]3 years ago
5 0
There both made up of substances
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How many mL of a 0.250M sodium hydroxide solution is needed to neutralize 25.0 mL of a 0.430M sulfuric acid solution?
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Answer:

86.0 mL

Explanation:

i just did the USA test prep

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3 years ago
A 1500 kg race car accelerates at a rate of about 9M /s2 as to how much force does the engine need to create for this to happen
IgorC [24]

Answer:

13500 N

Explanation:

According to newtons second law of motion

mass m =1500 Kg

a = 9m/s^2

Force F = mass m × acceleration a

F = 1500×9= 13500 N

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3 years ago
4.1 shows a plant cell. g For Examiner's Use n. C D Fig. 4.1 (i) Name the type of plant cell shown in Fig. 4.1. [1]​
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palisade cell due to presence of chloroplasts

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3 years ago
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called
Mademuasel [1]
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.

Answer: C) or the third option.
5 0
3 years ago
Read 2 more answers
The foul odor of rancid butter is due largely to butyric acid, a compound containing carbon, hydrogen, and oxygen. combustion an
Pavlova-9 [17]

Mass of CO₂ = 8.59 g  

Molar mass of CO₂ = 44 g/mol

Moles of CO₂ = Mass of CO₂ / Molar mass of CO₂ = 8.59 g  / 44 g/mol

                        = 0.1952 moles

Now there is 1 mole of C in 1 mole of CO₂

Therefore, moles of carbon = moles of CO₂ = 0.1952 moles

Mass of carbon = moles of C x  the atomic weight of C

                           = 0.1952 moles x 12 g/mol

                            = 2.3427 g

 Mass of H₂O = 3.52g  

Molar mass of H₂O = 18g/mol

Moles of H₂O =  3.52g /18g/mol = 0.1956 moles

Now there is 2 moles of H in 1 mole of H₂O

Moles of H = 0.1956 moles X 2  = 0.3912 moles

Mass of H = 0.3912 moles X atomic mass of H  

                 = 0.3912 moles X  1 g/mol = 0.3912 g

Mass of butyric acid = 4.30g  

Mass of O = mass of butyric acid - (mass of C + mass of H)

                  = 4.30 g - 2.3427 g - 0.3912 g = 1.5661 g

Moles of O = mass of O / atomic mass of O = 1.5661 g / 16 g/mol

                   = 0.0978 moles  

Divide by smallest mole to get the molar ratio  

C = 0.1952 moles/0.0978 moles  = 2

H =  0.3912 moles/0.0978 moles  = 4

O = 0.0978 moles  / 0.0978 moles  = 1

Empirical formula of butric acid is C₂H₄O  

Molecular formula of butric acid is C₄H₈O₂


3 0
3 years ago
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