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3 years ago

The slope of the line passes through the points (6,r) and (13,5) is 2/7. What is the value of r?

1 answer:

4 0

Slope=rise/run
another way to fid is
if you have points
(x1,y1) and (x2,y2)
slope is = (y2-y1)/(x2-x1)

we have points (6,r) an (13,5)

slope=2/7
2/7=(5-r)/(13-6)
2/7=(5-r)/(7)
multiply both sides by 7
2=5-r
minus 5
-3=-r
mult -1
3=r

r=3

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Write an algebraic expression for the statement.The income earned at $ 10.91 per hour for w hours....

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This is a "rate of pay" problem. The amount earned is equal to the (rate of pay) times the (number of hours worked).

Let the income be represented by "i". Then the formula is i = ($10.91/hour)*w, where w is the number of hours worked and has the unit of measurement "hours."

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2 years ago

A sample of size 200 will be taken at random from an infinite population. given that the population proportion is 0.60, the prob

Musya8 [376]

Let p be the population proportion. <span>
We have p=0.60, n=200 and we are asked to find P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60 and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is considered to be large and hence the sampling distribution of sample proportion-^p will follow the z standard normal distribution. Hence this sampling distribution will have the mean of all sample proportions- U^p = p = 0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] = √[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
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3 years ago

1. Supposed that a population consists of the values 1.2.3.4.5.6.7.8, 9, and 10. Construct

irina [24]

Answer:

Step-by-step explanation:

Just pick B bro it isn't even that hard lol

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3 years ago

Find the exact location of all the relative and absolute extrema of the function. HINT [See Examples 1 and 2.] (Order your answe

icang [17]

Answer:

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum (or "no absolute maximum")

Step-by-step explanation:

There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.

The derivative is ...

h'(t) = 24t^2 -48t = 24t(t -2)

This has zeros at t=0 and t=2, so that is where extremes will be located.

We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.

h(-1) = 8(-1)²(-1-3) = -32

h(0) = 8(0)(0-3) = 0

h(2) = 8(2²)(2 -3) = -32

h(∞) = 8(∞)³ = ∞

The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.

The extrema are ...

(-1, -32) absolute minimum
(0, 0) relative maximum
(2, -32) absolute minimum
(+∞, +∞) absolute maximum

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Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.

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3 years ago

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elixir [45]

Answer: 21

Step-by-step explanation:

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3 years ago