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adelina 88 [10]
4 years ago
6

A statistics student gave a survey to students which asked how many first cousins they have. The data from the first nine respon

ses are shown below.
6, 2, 7, 8, 8, 8, 5, 10, 10

What is the IQR of the data?

2.52 first cousins
3 first cousins
3.5 first cousins
8 first cousins
Mathematics
1 answer:
Anestetic [448]4 years ago
3 0

Given:

Date set for number of cousins is

6, 2, 7, 8, 8, 8, 5, 10, 10

To find:

The IQR of the data.

Solution:

We have,

6, 2, 7, 8, 8, 8, 5, 10, 10

Arrange the data ascending order.

2, 5, 6, 7, 8, 8, 8, 10, 10

Divide the data in two equal parts.

(2, 5, 6, 7), 8,( 8, 8, 10, 10)

Divide each parenthesis in two equal parts.

(2, 5), (6, 7), 8, (8, 8), (10, 10)

Now,

Q_1=\dfrac{5+6}{2}

Q_1=\dfrac{11}{2}

Q_1=5.5

and,

Q_3=\dfrac{8+10}{2}

Q_3=\dfrac{18}{2}

Q_3=9

The interquartile range (IQR) of the  data set is

IQR=Q_3-Q_1

IQR=9-5.5

IQR=3.5

The IQR is 3.5 first cousins.

Therefore, the correct option is C.

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3 years ago
ε = {x: 2 x 30, x is an integer}, M = {even numbers}, P = {prime numbers}, T = {odd numbers} Find: I) MUP ii) M - T iii) P(MT) i
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Answer:

Step-by-step explanation:

ε = {x: 2≤ x ≤30}

M = { even numbers} = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

P = { prime numbers} = {2,3,5,7,11,13,17,19,23,29}

T = {odd numbers} = {3, 5, 7, 9, 11,13,15,17,19,21,23,25,27,29}

1. M ∪ P = {2,3,4,5,6,7,8,10,11,12,13,14,16,17,18,19,20,22,23,24,26,28,29,30}

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(MT) = M ∩ T = 0

P ∪ (M ∩ T ) = {2,3,5,7,11,13,17,19,23,29}

4. P' = not a prime number

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P' ∪(M∩T')

P' ∪ {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30}

= {2,4,6,8,9,10,12,14,15,16,18,20,21,22,24,25,26,27,28,30}

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