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topjm [15]
4 years ago
14

WILL MARK BRAINLIEST!

Mathematics
1 answer:
Dmitry_Shevchenko [17]4 years ago
7 0

If you recall y=mx+b, the slope-intercept form of a linear equation, the slope, m, is the rate of change of the equation, and the y-intercept is b. 


When switching to function notation, we simply swap y for f(x), and if we start at x=0 and graph in the positive x direction, we've started at whatever initial value exists (the y-intercept value).


Simply: F(x) = 2/3 x +4

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Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2

Using logarithmic property, \logx^a=a\log x

\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Therefore, option B is correct.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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