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3 years ago

Kate paid $118.65 for a jacket. the price includes a 5% sales tax. how much was the jacket before the tax?

Mathematics

1 answer:

Harman [31]3 years ago

8 0

Let, the price of jacket before tax = x

it would be: x*105/100 = 118.65

x = 11865/105

x = $113

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Kruka [31]

Answer:

c.136

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3 years ago

What is The equivalent fraction of 2/5

Nat2105 [25]

Answer:

4/10 is equivalent to 2/5

Step-by-step explanation:

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7 0

3 years ago

Please help!!! How many coefficients does this polynomial have in its complete form, including any missing terms?

frez [133]

-5x^3 + 2x^2 + 1

a coefficient is the number that is multiplied by the variable.For instance, the coefficient of 2x is 2....because 2 (the number) is multiplied by the variable x.

so in ur problem....there are 2 coefficients..-5 and 2.

** the number 1 is not a coefficient, it is a constant...a " loner " with no variables (letters) attached.

** and if u have just the letter...such as n, the coefficient to that is 1 but the one is just not written...it is actually 1n.

okay...I am gonna shut up now :)

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3 years ago

Suppose 20 rabbits are taken to an island. the rabbit population then triples every year. the function f(x)

Zanzabum

$f(x) = 20*3^x$ $f(x) = 20*3^x$

hope this helps!

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5 0

3 years ago

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

3 years ago