Answer:
<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>
By De morgan's law
which is Bonferroni’s inequality
<h3>Result 1: P (Ac) = 1 − P(A)</h3>
Proof
If S is universal set then
<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>
Proof:
If S is a universal set then:
Which show A∪B can be expressed as union of two disjoint sets.
If A and (B∩Ac) are two disjoint sets then
B can be expressed as:
If B is intersection of two disjoint sets then
Then (1) becomes
<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>
Proof:
If A and B are two disjoint sets then
<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>
Proof:
If B is subset of A then all elements of B lie in A so A ∩ B =B
where A and A ∩ Bc are disjoint.
From axiom P(E)≥0
Therefore,
P(A)≥P(B)
Answer:
k = 7/6
Step-by-step explanation:
Answer:
Blank 1: 64° (or 32°, depending on what the label applies to)
Blank 2: 42
Step-by-step explanation:
It is a common mistake to believe you have solved the problem when you have found the value of the variable(s) in the problem. You have correctly found the values of n (42) and m (9). However, that is not what the problem is asking for.
We cannot tell if the value (1/2n+11)° is referring to angle DAB, or to angle CAB. In any event, (1/2n+11)° = (1/2×42 +11)° = 32°.
If that is angle CAB, then angle DAB is twice that value, 64°.
If that is angle DAB, then angle DAB is 32°.
__
The side length CD is the same as any other side length in a rhombus, so ...
CD = 4m+6 = 4×9 +6
CD = 42 . . . . units
Answer:
y = 2x
linear equations are just finding the right ratio and putting it in y = mx+b format
this graph is saying that two dollars are earned for every ticket sold, a 2:1 ratio.
so the equation would be y = 2x, two being the amount of money collected for one ticket, and x being the number of tickets sold.
