I need help with the questions

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

Hello

please find attached the graph

you can notice that $x^2-6x+9 = (x-3)^2$

(a) from the graph we can say that there is no maximum and one minimum in x = 3

and then f(3) = 0 so o is the minimum of f

(b) vertex is (3,0)

(d) as $x^2-6x+9 = (x-3)^2$ the root is 3

(e) y=9 for x = 0 so the y-intercept is 9

do not hesitate if you need further explanation

if you like my answer, tag it as the brainliest :-)

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(6x-9)+5=2 can you solve this

ehidna [41]

(6x -9) + 5= 2
= -54 + 5
= 2

7 0

3 years ago

Read 2 more answers

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$