Question

B is between line AC. If AB = x^2– 3x, BC = 9x, and AC = 16. Solve for x.

Answer 1

Answer:

x = {- 8, 2}

Step-by-step explanation:

Since, B is between line AC.

$\therefore AB + BC = AC\\\therefore x^2 - 3x + 9x = 16\\\therefore x^2 - 3x + 9x - 16=0\\\therefore x^2 + 6x - 16=0\\\therefore x^2 + 8x - 2x- 16=0\\\therefore x(x +8) - 2(x + 8)=0\\\therefore (x+8)(x-2)=0\\\therefore x + 8 = 0\: or \: x-2=0\\\therefore x = - 8 \:or\: x = 2\\\huge \orange {\boxed {\therefore x = \{-8,\: 2\}}}$