All categories

3 years ago

BRAINLIEST

Mathematics

2 answers:

Charra [1.4K]3 years ago

5 0

50 seconds because the two runners meet at that point since that is where the lines cross

Svetradugi [14.3K]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope this helps

You might be interested in

Justin is 2 years older than one third Marcella’s age. Aimee is 5 years younger than 2 times Justin’s age. Define a variable and

KIM [24]

Answer:

Step-by-step explanation:

J = (1/3)M + 2 <=== ur expression would be : (1/3)M + 2

A = 2J - 5

if marcella is 63....

J = (1/3 * 63) + 2 A = 2J - 5

J = 63/3 + 2 A = 2(23) - 5

J = 21 + 2 A = 46 - 5

J = 23 <== justin's age A = 41 <=== Aimee's age

4 0

3 years ago

Kevin wants buy a subwoofer for his truck. The one he wants cost $370.00. Kevin earns $14.00 for 5 problems, how many problems w

miskamm [114]

Kevin would have to write 133 problems, as 14/5= $2.8 per problem 370/2.8= 132.14 but since he can’t be paid to write .14 of a problem he needs to finish it making the answer 133 problems

4 0

3 years ago

PLS HURRY Point S is translated 5 units to the left and 12 units up to create point S'. Find the distance between point S and po

svet-max [94.6K]

Given:

Point S is translated 5 units to the left and 12 units up to create point S'.

To find:

The distance between the points S and S'.

Solution:

Point S is translated 5 units to the left and 12 units up to create point S'.

The diagram for the given problem is shown below.

From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.

By Pythagoras theorem,

$Hypotenuse^2=Perpendicular^2+Base^2$

$SS'^2=(12)^2+(5)^2$

$SS'^2=144+25$

$SS'^2=169$

Taking square root on both sides.

$SS'=\sqrt{169}$

$SS'=13$

Therefore, the distance between S and S' is 13 units.

8 0

3 years ago

Amy is helping plan her school's new basketball court. The west edge of the basketball court is located on the line y = 2x + 5.

lord [1]

Answer:

Step-by-step explanation:

hello :

The east edge cannot intersect with the west edge so :

the west edge and The east edge are paralal same slope but the slope for the line y = 2x + 5 is : 2

so : the line could the east edge be located is : y= 2x+b b : no 5

6 1

3 years ago

a piece of land 120 ft by 240 ft contains a circular garden. surrounding the garden, there is a circular fence that is 20 ft in

damaskus [11]

the area of the piece of land that is not part of the garden is $28,486ft^2$ .

<u>Step-by-step explanation:</u>

Here we have , a piece of land 120 ft by 240 ft contains a circular garden. surrounding the garden, there is a circular fence that is 20 ft in diameter. We need to find what is the area of the piece of land that is not part of the garden . Let's find out:

Let's calculate area of land and circular garden , and in order to find the area of the piece of land that is not part of the garden we will subtract area of circular garden from land !

Area of Land:

Area of land is given by

⇒ $length(width)$

⇒ $120(240)$

⇒ $28,880ft^2$

Area of Garden:

Area of circular garden given by

⇒ $\pi r^2$

⇒ $\pi (\frac{D}{2})^2$

⇒ $\pi (\frac{20}{2})^2$

⇒ $\pi (10)^2$

⇒ $100\pi$

⇒ $100(3.14)$

⇒ $314ft^2$

Hence , the area of the piece of land that is not part of the garden is 28,880-314 = 28,486 . Therefore , the area of the piece of land that is not part of the garden is $28,486ft^2$ .

8 0

3 years ago