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ivanzaharov [21]
3 years ago
9

Alrighty, last question guys! Someone, smarter than me can help, right? 50 points, sheesh i'm gonna be poor by the time i'm done

with these questions!

Mathematics
2 answers:
adelina 88 [10]3 years ago
7 0

Answer:

The answer is:-

Explanation:

  • Net A- Figure H
  • Net B- Figure G
  • Net C- Figure K
  • Net D- Figure J
Pie3 years ago
3 0

Answer:

AH, BG, CK, DJ

Cuboid, pyramid, prism, tetrahedron

Step-by-step explanation:

Nets A to D have the same number of shapes as the solids H, G, K and J respectively.

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5x + 2y=7<br> - 2x + 6y=9
ollegr [7]

Answer:

x = \frac{12}{17} or 0.706

y = \frac{59}{34} or 1.735

Step-by-step explanation:

5x + 2y=7    ----->(eq 1)

- 2x + 6y=9 ----->(eq 2)

Multiply (eq 1) with 3

3×(5x + 2y) = 3×7  

15x + 6y = 21  ----->(eq 3)

substract (eq 3) from (eq 2)

- 2x + 6y - (15x + 6y) = 9-21

- 2x + 6y - 15x - 6y = 9-21

- 2x - 15x + 6y - 6y = 9-21

-17x = -12

x = -12 ÷ -17

x = \frac{12}{17}

put x = \frac{12}{17} in (eq 1)

5*\frac{12}{17} + 2y = 7

2y = 7- 5*\frac{12}{17}

2y = \frac{7*17 - 60}{17}

2y = \frac{119- 60}{17}

2y = \frac{59}{17}

y = \frac{59}{17*2}

y = \frac{59}{34}

6 0
3 years ago
Logan walked 2 1/2 miles on Monday and she walked<br> 6 miles. How far did she walk on Tuesday?
Anon25 [30]

Answer:

3 1/2 miles

Step-by-step explanation:

because 6 - 2 1/2 = 3 1/2

5 0
2 years ago
12 – 7x ≤-2 <br> solve and show work
vova2212 [387]

Answer:

x≥2

Step-by-step explanation:

Let's solve your inequality step-by-step.

12−7x≤−2

Step 1: Simplify both sides of the inequality.

−7x+12≤−2

Step 2: Subtract 12 from both sides.

−7x+12−12≤−2−12

−7x≤−14

Step 3: Divide both sides by -7.

−7x/−7 ≤ −14/−7

x≥2

8 0
3 years ago
Find exact values for sin θ and cos θ if tan θ = -√3 and θ terminates in Quadrant II.
vivado [14]
Hello : 
<span>tan θ = -√3
sin</span>θ = √3/2    1/2                      
cosθ = -1/2   

5 0
3 years ago
The expression 3(x-9) is equivalent to
Inessa05 [86]
The answer to this question would be D. 3(x)-3(9)
8 0
3 years ago
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