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ololo11 [35]
2 years ago
13

What is a good way to remember how many ounces in a cup, etc...?

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
4 0
<span>Easy way to remember gallons, quarts, pints, and cups....</span>

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A standard deck of playing cards contains 52 cards, equally divided among four suits (hearts, diamonds, clubs, and spades). Each
Svetradugi [14.3K]
The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.
3 0
2 years ago
A
Evgesh-ka [11]
The answer will end up being c
6 0
3 years ago
Pls help me with this and an explanation
SCORPION-xisa [38]

Answer:

The relationship in this equation is linear, but not proportional. If it was proportional, then replacing x with nx should give ny as the answer. Example:

y = 3x

Replace x with 2x.

y' = 3(2x) = 2(3x) = 2y

y' = 2y

This is proportional. But if you replace x with 2x in

y = 3x + 5,

you will not get 2y for y'. This case is not proportiona

5 0
1 year ago
Read 2 more answers
Kwamee created a coffee blend for his cafe by mixing Kona beans and Fuji beans. Kona beans cost $11 per pound and Fuji beans cos
yKpoI14uk [10]
Let's use K for Kona and F for Fuji. The system of equations has to be a balanced system. For example, you can't mix the number of pounds of beans with the cost for each because pounds and dollars are different and you can only combine like terms...pounds with pounds and dollars with dollars. So let's start with the number of pounds. Since we don't know how much of each he bought we have the 2 unknowns, F and K, but we DO know that he bought 23 pounds total. So the first equation is
K + F = 23
Now let's see what we can do with the dollars. Again, we don't know how much he bought of each kind of coffee, but we do know that Kona beans cost $11 per pound and that Fuji beans cost $7.50 per pound, and we know that he spent a total of $197. So let's set that up:
11K + 7.50F = 197
Those are your 2 equations. It doesn't say you need to solve them, so you're done.
7 0
2 years ago
What is the product?
victus00 [196]

Answer:

\begin{bmatrix}-2\\0 \end{bmatrix}

Step-by-step explanation:

We have the product, 2\times \begin{bmatrix}-1\\0 \end{bmatrix}.

It is known that,

'When we multiply a scalar with a matrix, the scalar is multiplied by each element of the matrix'.

So, we get,

2\times \begin{bmatrix}-1\\0 \end{bmatrix}.

⇒ \begin{bmatrix}-1\times 2\\0\times 2 \end{bmatrix}

⇒ \begin{bmatrix}-2\\0 \end{bmatrix}

So, the resulting product is \begin{bmatrix}-2\\0 \end{bmatrix}.

8 0
2 years ago
Read 2 more answers
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