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Alex17521 [72]
2 years ago
5

How do this pleassssse

Mathematics
1 answer:
Inessa05 [86]2 years ago
3 0
X should also be 50° because they are corresponding angles.
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Find the distance between the points given.<br><br> (-1, -1) and (1, 3)<br><br> √5<br> √(17)<br> 2√5
Pani-rosa [81]

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5 0
2 years ago
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
Ilya [14]
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to A= \frac{LM+KN}{2} *MP= \frac{10+20}{2} *10=150 sq. units.


5 0
3 years ago
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